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3 years ago

How do i solve A sound wave has a frequency of 658 Hz in air

Physics

1 answer:

kiruha [24]3 years ago

6 0

Answer:

-47 °C

Explanation:

Speed of sound in air at sea level is:

v = 331 m/s + 0.6 m/s/°C T

where T is the temperature in Celsius.

The speed of sound is also the frequency times the wavelength:

v = fλ

Therefore:

fλ = 331 m/s + 0.6 m/s/°C T

(658 Hz) (0.46 m) = 331 m/s + 0.6 m/s/°C T

302.68 m/s = 331 m/s + 0.6 m/s/°C T

-28.32 m/s = 0.6 m/s/°C T

T = -47.2 °C

Rounding to two significant figures, the temperature is -47 °C.

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Rudiy27

Answer:

Vertical height of the hill, h = 20.4 meters

Explanation:

Given that,

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Solution,

Let h is the height of the hill. When he approaches the bottom of the hill, the loss in kinetic energy is equal to the gain in potential energy. Using the conservation of energy as,

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Two identical loudspeakers that are 5.00 m apart and face toward each other are driven in phase by the same oscillator at a freq

Lunna [17]

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Explanation:

Given

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Let $x_0$ be the smallest distance moved by observer then

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Position of observer w.r.t to second speaker is

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For Destructive interference

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For minimum m=0

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4 years ago

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inna [77]

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Explanation:

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