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3 years ago

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A group of friends are going to see a movie. The admission cost is $8 per person. The table below represents the number of frien

ds and the total cost
(2, 10), (3, 11), (4, 12), (5, 13)(2, 16), (3, 24), (4, 32), (5, 40)(10, 2), (11, 3), (12, 4), (13, 5)(16, 2), (24, 3), (32, 4), (40, 5)

2 answers:

andrew11 [14]3 years ago

8 0

Your answer for this question is either b or d

MAVERICK [17]3 years ago

6 0

Answer:

B) (2, 16), (3, 24), (4, 32), (5, 40)

Step-by-step explanation:

First, find the cost for 2,3,4 and 5 people to come to the movies.

Cost for Each Person- $8

Cost for 2 people- 8*2= $16

Cost for 3 people- 8*3= $24

Cost for 4 people- 8*4= $32

Cost for 5 people- 8*5= $40

List them as ordered pairs-

(2, 16), (3, 24), (4, 32), (5, 40)

formula- (x,y) (people,dollars)

x stands for # of people going and y stands for total amount $$

Thus, the answer is B

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F(x) = (x - 2)(x + 1)

Nana76 [90]

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Answer:

B, F

Step-by-step explanation:

The factors (x+1) cancel, leaving the function ...

f(x) = x -2

This is an odd-degree function with a positive leading coefficient, so its graph has the general shape / (up to the right). The end behavior is ...

as x → ∞, y → ∞
as x → -∞, y → -∞

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<em>Additional comment</em>

The graph of this function is a straight line with a slope of 1 and a y-intercept of -2. It has a hole (removable discontinuity) at (-1, -3).

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3 years ago

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sergiy2304 [10]

Answer:

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Step-by-step explanation:

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2 years ago

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Answer:

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3 years ago

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18 cajas de manzanas y peras fueron llevadas a la escuela. Las peras trajeron 210 kg en 6 cajas. ¿Cuántos kilos de manzanas fuer

Katyanochek1 [597]

Answer:

504 kilos de manzanas fueron llevados a la escuela.

Step-by-step explanation:

Sean $x$ , $y$ la cantidad de cajas de manzanas y peras, respectivamente. De acuerdo con el enunciado, tenemos el siguiente sistema de ecuaciones:

Total de cajas

$x+y = 18$ (1)

Masa de cada caja de peras

$y\cdot m_{P} = 210$ (2)

$y = 6$ (3)

Masa de caja de manzanas

$m_{M} = m_{P}+7$ (4)

De (2) en (3), tenemos que la masa de cada caja de peras es:

$m_{P} = 35\,kg$

Por (4), encontramos que la masa de cada caja de manzanas es:

$m_{M} = 35\,kg+7\,kg$

$m_{M} = 42\,kg$

Finalmente, de (1) tenemos la cantidad de cajas de manzana:

$x = 18-y$

$x = 12$

La cantidad de kilos de manzanas llevada a la escuela se obtiene al multiplicar la cantidad de cajas de manzana por la masa de cada caja:

$M = (12)\cdot (42\,kg)$

$M = 504\,kg$

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3 years ago

Which are the solutions of x2 = 19x + 1?

Finger [1]

Answer:

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

Step-by-step explanation:

we have

$x^2=19x+1$

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2}-19x-1=0$

so

$a=1\\b=-19\\c=-1$

substitute in the formula

$x=\frac{-(-19)\pm\sqrt{-19^{2}-4(1)(-1)}} {2(1)}$

$x=\frac{19\pm\sqrt{365}} {2}$

$x=\frac{19+\sqrt{365}} {2}$

$x=\frac{19-\sqrt{365}} {2}$

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

therefore

StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction

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3 years ago

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