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Marina86 [1]
3 years ago
11

You are taking a multiple-choice test that has 7 questions. Each of the questions has 5 choices, with one correct choice per que

stion. If you select one of these options per question and leave nothing blank, in how many ways can you answer the questions?
Mathematics
1 answer:
Vlad1618 [11]3 years ago
6 0

Answer:

78,125 ways

Step-by-step explanation:

Since each question has 5 answer options, then each question has 5 ways to answer it, therefore, for each question it would be:

1st question: 5 ways to answer yourself

2nd question: 5 ways to answer yourself

.

.

.

7th question: 5 ways to answer yourself

All the ways would be the total of the multiplication of each question, that is, 5 ^ 7, since there are 7 questions.

5 ^ 7 = 78125

There would be a total of 78,125 ways to answer the exam.

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Step-by-step explanation:

Given

(x^\frac{3}{8})^\frac{3}{4}

Required

Convert to radical form

(x^\frac{3}{8})^\frac{3}{4}

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(x^\frac{3}{8})^\frac{3}{4} = x^\frac{3*3}{8*4}

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