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4 years ago

15

Use complete sentences to explain why it is not possible to simplify the following trigonometric expression.

2 answers:

Alja [10]4 years ago

8 0

Answer:

Arcsin(X) is the inverse function of the Sin function.

This means that Arcsin(X) gives you the value Y that you need to input in the function of Sin in order to have Sin(Y) = X

Here you can see that we have Arcsin(2), this would be equal to a number that when you put it inside the sin function, you have

Sin(Y) = 2, but as you know, the range of the sin function is from -1 to 1, so you never can have Sin(Y) = 2, this is why this expression can not be simplified.

Kay [80]4 years ago

5 0

This is not possible because arcsin is the angle that will give you a sine value of 2. Sine values range from -1 to 1; there is no angle that will give you a sine of 2.

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A gallon of milk costs $3 nowIf the price is increasing 10% per year, how long before a gallon of milk costs $10 a gallon? Round

r-ruslan [8.4K]

Answer:

The answer is 33 years.

Step-by-step explanation:

10% of 3 is .3

Just move the decimal to the left.

.3 times 33=9.9

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3 years ago

Two particles move in the xy-plane. At time t, the position of particle A is given by x(t)=5t−5 and y(t)=2t−k, and the position

Ipatiy [6.2K]

Answer:

Part A) Not collide

Part B) k = 4

Part C) Particle B is moving fast.

Step-by-step explanation:

Two particles move in the xy-plane. At time, t

<u><em>Position of particle A:-</em></u>

$x(t)=5t-5$

$y(t)=2t-k$

<em><u>Position of particles B:-</u></em>

$x(t)=4t$

$y(t)=t^2-2t+1$

Part A) For k = -6

Position particle A, (5t-5,2t+6)

Position of particle B, $(4t,t^2-2t-1)$

If both collides then x and y coordinate must be same

Therefore,

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t+6=t^2-2t-1$

$t^2-4t-7=0$

$t=-1.3,5.3$

The value of t is not same. So, k = -6 A and B will not collide.

Part B) If both collides then x and y coordinate must be same

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t-k=t^2-2t-1$

Put t = 5

$10-k=25-10-1$

$k=4$

Hence, if k = 4 then A and B collide.

Part C)

Speed of particle A, $\dfrac{dA}{dt}$

$\dfrac{dA}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dA}{dt}=2\cdot \dfrac{1}{5}\approx 0.4$

Speed of particle B, $\dfrac{dB}{dt}$

$\dfrac{dB}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dB}{dt}=2t-2\cdot \dfrac{1}{4}$

At t = 5

$\dfrac{dB}{dt}=10-2\cdot \dfrac{1}{4}=2$

Hence, Particle B moves faster than particle A

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3 years ago

(a) State whether each of the following is a function. (6, 2), (8,2), (6,3), (12,3) Yes / No

Sloan [31]

Answer:

Not a function.

Step-by-step explanation:

The definition of a function specifies that no value of <em>x</em> can be paired with two or more different values of <em>y</em>.

In the given relation: {(6, 2), (8, 2), (6, 3), (12, 3)},

The input value of x = 6 has two corresponding output values (y-coordinates): 2 and 3.

Therefore, the given relation is not a function.

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3 years ago

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Answer:

The square root of 2 over 2

Step-by-step explanation:

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