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Mademuasel [1]
3 years ago
9

Find a and b so that the polynomial, p(x)=x^2+ax-b passes through the points (6,-9) and (1, 16)

Mathematics
1 answer:
tatuchka [14]3 years ago
3 0

The given equation is:

p(x) = x^2 + ax - b

We write this in terms of y:

y = x^2 + ax – b

To solve for the values of the constants a and b, we are given the following conditions:

When x = 6, y = -9

When x = 1, y = 16

From these conditions, we can formulate two equation by substituting the values of y:

-9 = 6^2 + a(6) – b

6a = b – 45                           ---> 1

 

16 = 1^2 + a(1) – b

a = b + 15                             ---> 2

 

Combining equations 1 and 2:

6 (b + 15) = b – 45

6b + 90 = b – 45

5b = -135

b = -27

 

calculating for a using equation 1:

a = b + 15

a = -27 + 15

a = -12

 

Answers:

a = -12

b = -27

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<h3><u>Solution</u></h3>

<u>Given </u><u>:</u><u>-</u>

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<u>F</u><u>i</u><u>n</u><u>d</u><u> </u><u>:</u><u>-</u>

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<h3 /><h3><u>Explantion</u></h3>

<u>Using </u><u>Formula</u>

\boxed{\underline{\tt{\red{\:(perimeter_{rectang}\:=\:2\times (Length+Width)}}}}

<u>Let,</u>

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  • Breadth of Rectangle = y cm

<u>According</u><u> to</u><u> question</u><u>,</u>

==> perimeter of Rectangle = 72

==> 2(x+y) = 72

==> x + y = 72/2

==> x + y = 36_________________(1)

<u>Again,</u>

==> x = 2y + 3

==> x - 2y = 3__________________(2)

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==> y + 2y = 36 - 3

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==> y = 33/3

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<u>keep </u><u>in </u><u>equ(</u><u>1</u><u>)</u>

==> x - 2×11 = 3

==> x = 3 + 22

==> x = 25

<h3><u>Hence</u></h3>

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<h3 />

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