$ 75000 is the maximum amount that he can spend per month paying off credit cards and loans and not be in danger of credit overload.
More than this amount will exceed his income.
Motion Capture. "it's a combination of rotoscoping with newer computer technology, allowing people to use live footage as the basis for animation without having to go through the process of drawing over it." -scienceworld .ca
Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
Answer:
Identify the location of the college stand in advance.
Explanation:
One way to save time and get to the colleges that you are most interested in at a college fair is to find out in advance the information about the fair, the colleges that are participating and from that pick the more interesting ones and identify the location of their stands. Like that when you arrive to the fair you can go directly to them and find them easily which will save you a lot of time as you won't be walking around the whole place to find them.
