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Marta_Voda [28]
3 years ago
8

Frances can complete 91 oil changes in 7 days.

Mathematics
2 answers:
baherus [9]3 years ago
8 0
91 / 7 = 13; 13 * 11 = (143 oil changes)
joja [24]3 years ago
5 0
Ratio problem:

91 changes = 7 days
-----------------   --------
          x            11 days

7x = 1001
x = 143
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Which of the following gives the correct intercept points and vertex point for the function ƒ(x) = x2 + 5x + 6?
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Answer:

(-5/2,-1/4)

Step-by-step explanation:

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What’s the area for this shape? I don’t know what the formula is
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Answer: 148.92in2

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Suppose that 80 percent of all statisticians are shy, whereas only 15 percent of all economists are shy. Suppose also that 90 pe
Anna71 [15]

Answer:

37.21% probability that the person is a statistician.

Step-by-step explanation:

We have these following probabilities:

An 80% probability that a statistican is shy.

A 15% probability that an economist is shy.

At the gathering, a 90% probability that a person is an economist.

At the gathering, a 10% probability that a person is a statistican.

If you meet a shy person at random at the gathering. What is the probability that the person is a statistician?

This can be formulated as the following question:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

What is the probability that the person is a statistican, given that he is shy?

P(B) is the probability of the person being a statistican. So P(B) = 0.1.

P(A/B) is the probability of a statistican being shy, so P(A/B) = 0.8.

P(A) is the probability of a person being a shy. This is 15% of 90%(economists) and 80% of 10%(statisticans). So

P(A) = 0.15*0.9 + 0.8*0.1 = 0.215

Finally

P = \frac{P(B).P(A/B)}{P(A)}

P = \frac{0.1*0.8}{0.215} = 0.3721

37.21% probability that the person is a statistician.

3 0
4 years ago
During a dig, an archaeological team starts at an elevation of −512 feet. At a rate of 234 feet per hour, the team digs deeper i
creativ13 [48]
Are you referring to this question?
During a dig, an archaeological team starts at an elevation of −5 1/2 feet. At a rate of 2 3/4 feet per hour, the team digs deeper into the surface for 3 1/2 hours. For the next 4 1/2 hours, the team digs at a rate of 1 5/12 feet per hour. Then the team quits for the day.
How many feet did the archaeological team dig after 3 1/2 hours?
<span>What was the team's elevation at the end of the day?
</span>
If so, then let us find out the elevation.

The rate of their dig is 2 3/4 ft per hr for 3 1/2 hours, then the total distance dug after 3 1/2 hours should be: 9 5/8 ft

Here’s how we get the total distance:

 First, change mixed number into improper fraction and proceed to multiplication

2 3/4--> 11/4  and  3 1/2  becomes 7/2

Multiply.

11/4  x  7/2  = 77/8

Simplify 77/8--> 9 5/8 ft

 

Let us move on at the rate of 1 5/12 ft per hr for the next 4 1/2 hr,

Following the same procedure as above, the distance would be: 6 9/24 ft

 

Distance= 1 5/12 x 4 1/2

       = 17/12 x 9/2

       = 153/24

       = 6 9/24 ft

 

Thus,to sum up everything, they have a total dug of:

 9 5/8 + 6 9/24 = 9 15/24 + 6 9/24 = 16 ft

 

Then, their elevation on that day<span> is -5 1/2 - 16 = -21 1/2 ft</span>

5 0
4 years ago
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