Answer:
Step-by-step explanation:
Since there are a total of 4 colors, and there are 5 of each colors, the total marbles in the bad would be;
5 x 4 = 20
If a color is selected at random the probability would be
our part is 5
our whole is 20
so the probability would be;
or
when reduced
Hope this helps!
Answer:
a) 2.84% probability that he is late for his first lecture.
b) 5.112 days
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
a. Find the probability that he is late for his first lecture.
This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So
has a pvalue of 0.9716
1 - 0.9716 = 0.0284
2.84% probability that he is late for his first lecture.
b. Find the number of days per year he is likely to be late for his first lecture.
Each day, 2.84% probability that he is late for his first lecture.
Out of 180
0.0284*180 = 5.112 days
Answer: 14 members take physics but not mathematics
Step-by-step explanation:
Please see the attached for a diagrammatic representation of this situation.
Since there are 40 members but 8 did not offer any of mathematics or physics, then:-
40 - 8 = 32
So, 32 members of the fraternity offer maths, physics or both.
5 members offer both mathematics and physics .
Since 5 members offer both mathematics and physics, the number of members that offer maths alone = 18 - 5
Let us use "P" to represent the number of members that offer physics. Therefore, the number of members that offer only physics = (P - 5)
Now, if we add up the members that offered maths only, the members that offered both mathematics and physics and the members that offered only physics, it will be equal to the 32 members that offered at least a subject.
Therefore, (18 - 5) + 5 + (P - 5) = 32
18 - 5 + 5 + P - 5 = 32
18 + P - 5 = 32
P + 13 = 32
P = 32 - 13
P = 19
19 members offered physics out of the 32 members that offered maths, physics or both.
To find out the number of people or members that offered physics only, we subtract the number of members that offered the two subjects (5) from a total of 19 members that offered Physics
19 - 5 = 14
Therefore, 14 members of the fraternity offer only physics
