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posledela
3 years ago
5

√385848774575778384834

Mathematics
2 answers:
grandymaker [24]3 years ago
5 0
1.964303374E10 this should be right, after all I out it in my calculator. Hope this helps :)
Reil [10]3 years ago
3 0
19,643,033,741.6545305...
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Please help me with this question. i would really appreciate it!
NemiM [27]

Answer:

it should be c or d

Step-by-step explanation:

5 0
3 years ago
Is y=x^2-2x-35 standard form or vertex form
Degger [83]

Answer:

Standard Form

Step-by-step explanation:

Vertex form would be: (x-1)^2- 36

7 0
4 years ago
Read 2 more answers
How do you rationalize the numerator in this problem?
maw [93]

To solve this problem, you have to know these two special factorizations:

x^3-y^3=(x-y)(x^2+xy+y^2)\\ x^3+y^3=(x+y)(x^2-xy+y^2)

Knowing these tells us that if we want to rationalize the numerator. we want to use the top equation to our advantage. Let:

\sqrt[3]{x+h}=x\\ \sqrt[3]{x}=y

That tells us that we have:

\frac{x-y}{h}

So, since we have one part of the special factorization, we need to multiply the top and the bottom by the other part, so:

\frac{x-y}{h}*\frac{x^2+xy+y^2}{x^2+xy+y^2}=\frac{x^3-y^3}{h*(x^2+xy+y^2)}

So, we have:

\frac{x+h-h}{h(\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2})}=\\ \frac{x}{\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2}}

That is our rational expression with a rationalized numerator.

Also, you could just mutiply by:

\frac{1}{\sqrt[3]{x_h}-\sqrt[3]{x}} \text{ to get}\\ \frac{1}{h\sqrt[3]{x+h}-h\sqrt[3]{h}}

Either way, our expression is rationalized.

7 0
4 years ago
Please give question for the answer.
fenix001 [56]

Answer:

f(x)=\sqrt[3]{x} \\a=5

Step-by-step explanation:

f(x)=\sqrt[3]{x} \\a=5

3 0
3 years ago
Read 2 more answers
The difference between two num-
bekas [8.4K]

Answer:

51 and  -27

Step-by-step explanation:

The sum of two numbers is 24 and their difference is 78. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 24. In other words, x plus y equals 24 and can be written as equation A:

x + y = 24

The difference between x and y is 78. In other words, x minus y equals 78 and can be written as equation B:

x - y = 78

Now solve equation B for x to get the revised equation B:

x - y = 78

x = 78 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 24

78 + y + y = 24

78 + 2y = 24

2y = -54

y = -27

Now we know y is -27. Which means that we can substitute y for -27 in equation A and solve for x:

x + y = 24

x + -27 = 24

X = 51

Summary: The sum of two numbers is 24 and their difference is 78. What are the two numbers? Answer: 51 and -27 as proven here:

Sum: 51 + -27 = 24

Difference: 51 - -27 = 78

4 0
3 years ago
Read 2 more answers
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