Nikita's distance from her for the second part of the race was 1.5 kilometers.
Since Nikita ran a 5-kilometer race in 39 minutes (0.65 of an hour) without training beforehand, and in the first part of the race, her average speed was 8.75 kilometers per hour, while for the second part of the race, she started to get tired, so her average speed dropped to 6 kilometers per hour, to determine which expression represents Nikita's distance for the second part of the race the following calculation must be performed:
- 8.75 x 0.65 + 6 x 0 = 5.68
- 8.75 x 0.50 + 6 x 0.15 = 5.275
- 8.75 x 0.40 + 6 x 0.25 = 5
-
100 = 60
- 40 = X
- 40 x 60/100 = X
- 24 = X
- 39 - 24 = 15
- 15 = 1/4 hour
- 6/4 = 1.5
Therefore, Nikita's distance from her for the second part of the race was 1.5 kilometers.
Learn more about maths in brainly.com/question/22791791
Answer:
3.28
Step-by-step explanation:
find the mean of all the numbers
3 + 8 + 10 + 12 + 15 = 48
48/5=9.6
so the mean of all the numbers is 9.6
now subtract 9.6 from all the numbers
|3 - 9.6| = 6.6
|8 - 9.6| = 1.6
|10 - 9.6| = .4
|12 - 9.6| = 2.4
|15 - 9.6| = 5.4
Find the mean/average of the new values
6.6 + 1.6 + .4 + 2.4 + 5.4 = 16.4
16.4/5 = 3.28
Log ( base 2 ) ( 1 / 4 ) =
= log ( base 2 ) ( 2 ^(-2 ) ) =
= - 2 log ( base 2 ) 2 = ( because : log x^n = n log x )
= ( - 2 ) * 1 = ( because: log (base x) x = 1 )
= - 2
Since 10^30 is less than 10^33
That means the unit of measure is greater than grams.
The final answer is kilograms
Answer:
a²+b²=c²
7.5²+9²=c²
137.25=c²
√137.25=c²
11.72.... = c
The Radius of the circle is approximately 11.72cm
Step-by-step explanation:
Using this data. Create a Triangle with the Chord and Center of the dot. We know the distance between the chord and center which is one length of one of the sides.
We split the chord from the intersecting line from the center to the chord making the second line being 7.5cm
After We draw a line from the center of the circle to where the chord meets to the edge of the circle to create the triangle
We now have 2 measurements and can use Pythagorean Theorem to determine the radius from the missing length of the triangle.
