The number of school buses needed to transport students on a field trip is given by the function f(x) = x/40. What if the domain
1 answer:
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<span>Let's analyze Hannah's work, step-by-step, to see if she made any mistakes.
</span>In Step 1, Hannah wrote
<span> as the sum of two separate derivatives </span>
<span>using the </span><span>sum rule.
</span>
This step is perfectly fine.
In Step 2,
was kept as it is, and 
was rewritten as 
using the constant rule.Indeed, according to the constant rule, the derivative of a constant number is equal to zero.
This step is perfectly fine.
In Step 3,
was rewritten as 
supposedly using the constant multiple rule.
The problem is that according to the constant multiple rule,
should be rewritten as 
and not as 
.
<span>Therefore, Hannah made a mistake in this step.</span>
</span>In Step 1, Hannah wrote
</span>
This step is perfectly fine.
In Step 2,
This step is perfectly fine.
In Step 3,
The problem is that according to the constant multiple rule,
<span>Therefore, Hannah made a mistake in this step.</span>
Answer:
b) 9x² - 3x
Step-by-step explanation:
Area of a rectangle = Length × Width
Area for the rectangle = 3x - 1 × 3x
Area =
Step 1. Multiply by combining like terms
3x · 3x = 9x²
Step 2. Multiply -1 by 3x
-1 · 3x = -3x
Step 3. Combine 9x² and -3x
9x² - 3x
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You need to implement the process of "flip-flop" and multiply which is where you flip the second fraction and multiply.
÷
⇒×
Now you multiply across. 2×15=30 and 3×11=33
So now it is
-----------------------------------------------------------
To reduce to the lowest terms, find the GCF common factor
The GCF is 3
Divide both the numerator and denominator by 3
÷
=
Answer:
Now you multiply across. 2×15=30 and 3×11=33
So now it is
-----------------------------------------------------------
To reduce to the lowest terms, find the GCF common factor
The GCF is 3
Divide both the numerator and denominator by 3
Answer: