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shusha [124]
3 years ago
6

The number of school buses needed to transport students on a field trip is given by the function f(x) = x/40. What if the domain

of this function? Please explain.
A. x is the set of all real numbers

B. x is the set of all integers

C. x is the set of all non-negative integers

D. x is the set of all non-negative real numbers
Mathematics
1 answer:
Anika [276]3 years ago
4 0
The domain of the function are all the values of x that are possible for the given equation and that will make the equation true. Since the number of buses cannot be a fraction, the values of x should be divisible by 40. The answer to this item should be letter B. 
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Write an equation of the line that passes through (4,-1) and is parallel to the line -3x +y= 7
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Answer:

y = 3x -13

Step-by-step explanation:

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2 years ago
(4x-4)+(3x-2)+(2x+6)=180
Ahat [919]

Answer:

x=20

Step-by-step explanation:

Let's solve your equation step-by-step.

4x−4+3x−2+2x+6=180

Step 1: Simplify both sides of the equation.

4x−4+3x−2+2x+6=180

4x+−4+3x+−2+2x+6=180

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Step 2: Divide both sides by 9.

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9

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x=20

6 0
3 years ago
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He should change how much he puts into his account each month to $50
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What is the distance from the origin to point P graphed on the complex plane below?
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Evaluate the following integral using trigonometric substitution.
wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function \int\limits {\sqrt{a^{2} -x^{2} } } \, dx, using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as asin \theta i.e x = a sin\theta.

All integrals in the form \int\limits {\sqrt{a^{2} -x^{2} } } \, dx are always evaluated using the substitute given where 'a' is any constant.

From the given integral, \int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx where a = 7 in this case.

The substitute will therefore be   x = 7 sin\theta

2.) Given x = 7 sin\theta

\frac{dx}{d \theta} = 7cos \theta

cross multiplying

dx = 7cos\theta d\theta

3.) Rewriting the given integral using the substiution will result into;

\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta  } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)}   } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)}   } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)}   } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)}   }}} \, 7cos\theta d\theta\\

= \int\limits343 cos^{2}  \theta \, d\theta

8 0
3 years ago
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