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Ostrovityanka [42]
3 years ago
14

Evaluate 12 x (4^-2/4^-4) A 1/4 B 3/4 C 16 D 192

Mathematics
1 answer:
MrMuchimi3 years ago
7 0
12 ×4^4/4^2
=12×4^2
=12×16
=192
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The diameter of the average cell in the human body is 1 x 10-5 meters. The diameter of a grain of sand is about 2 x 10-4 meters.
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PART A:

Scientific notation is given by A×10ⁿ where A is any number in a unit and 'n' is an integer.

0.000025 = 2.5×10⁻⁵

PART B:

Diameter of grain of sand ÷ Diameter of human body average cell
(2×10⁻⁴) ÷ (1×10⁻⁵) 
(2÷1) × (10⁻⁴÷10⁻⁵)
2 × (10⁻⁴ ⁻ ⁻⁵) = 2 × 10⁽⁻⁴⁺⁵⁾ = 2 × 10¹ = 20 times bigger

PART C:

The diameter of human body's average cell in nanometer
1 × 10⁻⁵ metre = 1 × 10⁻⁵ × 10⁹ = 1 × 10⁽⁻⁵⁺⁹⁾ = 1 × 10⁴ nanometer

PART D:

Smallest bacteria = 300 nanometer
300 nm = 300 ÷ 10⁹ = (3 × 10²) ÷ 10⁹ = 3 × (10²⁻⁹) = 3 × 10⁻⁷ meter

PART E:

Laws of exponents that are applied in scientific notation is 

xᵇ × xᵃ = x⁽ᵇ⁺ᵃ⁾
xᵇ ÷ xᵃ = x⁽ᵇ⁻ᵃ⁾

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Which table represents a function?
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B represents a function ✔️
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How many gallons of paint would you need to paint a dog house that is 372ft in total?
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It would be 44gallons
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Jade is going out for pizza with her friend.For 60 dollars how many pizzas can she buy if each pizza costs 12 dollars
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1) The population of a town was7652in 2016. The population grows at a rate of 1.6%annually.(a)Use the exponential growth model t
marshall27 [118]

Answer:

1. a) population of the town in 2024 = 8697

2.) the earthquake with a magnitude of 8 is a <u>100 times stronger</u> than an earthquake with a magnitude of 6.

Step-by-step explanation:

1) the population of a town was, N_{0}   = 7652 in 2016.

a) Exponential growth model is given by N(t) = N_{0} e^{kt} where t is the time in years after 2016.

 Year 2016 is when t = 0.

  k = growth rate constant = 1.6% = 0.016

 i) therefore the population of the town in 2024

    = N = N_{0} e^{kt}  = 7652e^{0.016\times8}  = 8697   ( to the nearest whole number)

2.) log (I \times M \times S) = magnitude of earthquake  where I is the Intensity of the earthquake and S is the intensity of a standard earthquake

therefore  I \times M \times S = 10^{magnitude\hspace{0.1cm}of\hspace{0.1cm}earthquake}

therefore \frac{strength\hspace{0.1cm}of\hspace{0.1cm}earthquake\hspace{0.1cm}1 }{strength\hspace{0.1cm}of\hspace{0.1cm}earthquake\hspace{0.1cm}2}  = \frac{10^{8} }{10^{6} }  = 100

 

3 0
3 years ago
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