1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dimulka [17.4K]
3 years ago
8

Put the following products in order from greatest to least 6x 2/5 , 3 2/3 x 2/5, 2/7 X 2/5, 2/2 x2/5

Mathematics
1 answer:
DedPeter [7]3 years ago
6 0
6x2/5>3 2/3x 2/5>2/2x2/5>2/7x2/5
You might be interested in
20 = 7x + 2 - 4x <br> What does x equal
saveliy_v [14]

Answer:

x = 6

Step-by-step explanation:

20 = 7x + 2 - 4x

7x + 2 - 4x  = 20    (switch the sides)

7x - 4x + 2 = 20     (group the like terms together)

3x + 2 = 20            (add similar numbers, in this case it's the both x's)

    -2     -2              (subtract 2 on both sides)

------------------

3x = 18

/3     /3                   (divide both sides by 3)

-------------------

x = 6

5 0
2 years ago
Read 2 more answers
Which is greater 10 centimeters or 103 millimeters?​
Yuliya22 [10]

Answer: 103 mm

Step-by-step explanation: The conversion factor from centimeters to millimeters is 10, which means that 1 centimeter is equal to 10 millimeters: 1 cm = 10 mm. To convert 103 centimeters into millimeters we have to multiply 103 by the conversion factor in order to get the length amount from centimeters to millimeters.

3 0
2 years ago
Read 2 more answers
A climber starts at an elevation of -200 meters and her change in elevation is 300 meters up. What is her final elevation?
kherson [118]

Answer:

100

Step-by-step explanation:

because -100 0 then positive 100      

                     

4 0
2 years ago
A girl is flying a kite with a 120ft string attached to the ground is flying directly Selena’s head is standing 24 ft from where
SashulF [63]

Answer:

111.58 feet

Step-by-step explanation:

Given that the length of the string (AB in the attached diagram) is 120 feet.

Selena (at point D) is standing 24 feet from point A, where the kite is attached to the ground.

Since the kite is directly above Selena's head, the problem forms a right triangle.

Using Pythagoras theorem

|AB|^2=|BD|^2+|AD|^2\\120^2=|BD|^2+24^2\\|BD|^2=120^2-24^2\\|BD|^2=13824\\|BD|=\sqrt{13824} \\|BD|=117.58$ ft

Serena's height (CD=6 feet)

The distance of the kite above her head is BC in the drawn diagram.

Therefore:

|BD|=|BC|+|CD|

117.58=|BC|+6

|BC|=117.58-6

|BC|=111.58 feet

The kite is approximately 111.58 feet above Selena's head/

5 0
3 years ago
According to the line of best fit, what is the best estimate of projected sales in thousands of dollars for 2018?
Iteru [2.4K]
About $43,000 because if you look on the graph, look for 2018 and go up until you meet the line. Then, using that, you can move left to the sales indication. The line hits 2018 between 40,000 and 45,000, so it is $43,000.
5 0
3 years ago
Read 2 more answers
Other questions:
  • 23. Which is a solution to the inequality below?
    10·1 answer
  • The weight limit for freight loaded onto a freight elevator is 7500 pounds. If each crate weighs 375 pounds, how many crates, c,
    7·1 answer
  • How to add mixed numbers
    5·2 answers
  • Sqareroot 12 - (sqr. 3) = ?
    7·1 answer
  • A circular lid has a diameter of 12 inches. What is the exact area of the lid? A. 6π square inches B. 12π square inches C. 24π s
    8·1 answer
  • 4. The students in Mr. Michael’s art class are decorating a booth for Harvest Day. They have blue cloth that is 60 inches long,
    14·1 answer
  • 12. When 64 is divided by x, the quotient is a negative
    12·1 answer
  • What is the weight of a square if a triangle weighs 4 grams? Explain your reasoning
    12·1 answer
  • Does the equation “y = x/10” represent a proportional relationship?
    13·1 answer
  • Find the principal needed now (the present value) in order to get $10,000 after 15 years, compounded
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!