Question

Line l has equation y=-3. Find the distance between l and the point E(-7,0).

Answer 1

Wait... why the nearest tenth? maybe i’m reading the questions wrong but the equation y=-3 is just a horizontal line going through -3 on the y axis, so the diff is just 4

Answer 2

Answer:

The given line has slope m=1

the perpendicular line MUST have slope -1

Since it MUST eat (-3,2), the intercept formula says

B = y - mx = 2 - (-1)(-3)  = 2 - 3 = -1

so the equation of the perpendicular line that eats point W is

y = -x -1

The lines y=x+3 and it's perpendicular y = -x-1 intersect at

  y = x+3 = -x-1

   2x+3 = -1

  2x = -4

  x = -2

THe intersection point is

(-2,1)

Finally by distance formula,

The distance between (-3,2) and (-2,1) is

 sqrt ( (-3 - -2)^2 + ( 2-1)^2)

= sqrt( (-3 + 2)^2 + (2-1)^2)

 = sqrt( (-1)^2 + 1^2)

  = sqrt ( 1+1)

 = sqrt(2)

Step-by-step explanation: