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tino4ka555 [31]
3 years ago
13

A temprature change in a reaction indicates

Chemistry
1 answer:
umka21 [38]3 years ago
3 0

Chemical change

Explanation:

Often times, in chemical reactions, a temperature change indicates that a chemical change has occurred.

What is a chemical change?

  • It is a kind of change in which new products are formed.
  • Chemical changes are usually accompanied by energy changes in reactions.
  • The process is not easily reversible.
  • It usually involve a change in mass.
  • Requires considerable amount of energy

When temperature change occurs, it usually denotes chemical change.

learn more:

Chemical change brainly.com/question/9388643

#learnwithBrainly

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If the volume of the container is decreased to  90.0 ml and the pressure is increased to 1.60 atm the temperature will be 302 °K

Explanation:

Boyle's law says that "The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure", which is expressed mathematically as:  

P * V = k

Charles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, by means of a proportionality constant that is applied directly. In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

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\frac{P}{T}=k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

\frac{P*V}{T}=k

Having a state 1 at the beginning and a state 2 at the end is fulfilled:

\frac{P1*V1}{T1}=\frac{P2*V2}{T2}

In this case, you know:

  • P1= 0.800 atm
  • V1= 180 mL= 0.180 L (being 1 L=1000 mL)
  • T1= 29 °C= 302 °K
  • P2= 1.60 atm
  • V2= 90 mL= 0.09 L
  • T2=?

Replacing:

\frac{0.800 atm*0.180L}{302 K}=\frac{1.60 atm*0.09L}{T2}

Solving:

T2*\frac{0.800 atm*0.180L}{302 K}=1.60 atm*0.09L

T2=\frac{1.60 atm*0.09L}{\frac{0.800 atm*0.180L}{302 K}}

T2= 302 °K

<em><u>If the volume of the container is decreased to  90.0 ml and the pressure is increased to 1.60 atm the temperature will be 302 °K</u></em>

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