Question

The amount of gas that occupies 36.52 L at 68.0 degrees Celsius and 672 mm Hg is ___ Mol.

Answer 1

1.15 moles

Explanation:

The ideal gas law is written as  $PV=nRT$

where $P,V,T$are the pressure, volume and temperature,$n$ is the number of moles of gas; and $R$ is the ideal gas constant. It is the same for all gases.

Given,$P=672 mm of Hg=0.8842 \text{ atm}$

$V=36.52L$

$T=$$68^{0} C=$$341.15K$

$R=0.0821\text{ atm L }moles^{-1}K^{-1}$

Since,$n=\frac{PV}{RT} =\frac{0.8842\times 36.52}{0.0821\times 341.15}=1.15$

So,the number of moles is $1.15$