Answer:
The rate at which both of them are moving apart is 4.9761 ft/sec.
Step-by-step explanation:
Given:
Rate at which the woman is walking,
= 3 ft/sec
Rate at which the man is walking,
= 2 ft/sec
Collective rate of both,
= 5 ft/sec
Woman starts walking after 5 mins so we have to consider total time traveled by man as (5+15) min = 20 min
Now,
Distance traveled by man and woman are
and
ft respectively.
⇒ 
⇒ 
As we see in the diagram (attachment) that it forms a right angled triangle and we have to calculate
.
Lets calculate h.
Applying Pythagoras formula.
⇒
⇒ 
Now differentiating the Pythagoras formula we can calculate the rate at which both of them are moving apart.
Differentiating with respect to time.
⇒ 
⇒ 
⇒
...as 
⇒ Plugging the values.
⇒
...as
ft/sec
⇒
ft/sec
So the rate from which man and woman moving apart is 4.9761 ft/sec.
6x + 8y = 24
6(4) + 8(0) = 24
Step-by-step explanation:
→ 42 = 7u - u
→ 42 = 6u
→ 42/6 = u
→ 7 =u or U = 7
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Your answer is B Hope I helped :)
Answer:
y =7
x =14
Step-by-step explanation:
Since this is a right triangle we can use trig functions
tan 30 = opp /adj
tan 30 = y/ 7 sqrt(3)
7 sqrt(3) tan 30 = y
7 sqrt(3) * 1/ sqrt(3) =t
7 =y
sin 30 = opp/ hyp
sin 30 = 7/x
x sin 30 =7
x = 7/ sin 30
x = 7 / 1/2
x = 14