32ft/sec to meters/sec

At age 25, Gherman Titov was the youngest person to travel into space. This is 52 years less than the oldest

r-ruslan [8.4K]

Answer:

77 years old

Step-by-step explanation:

3 0

3 years ago

Unit 11: volume & surface area homework 8

Sholpan [36]

The volumes of the pyramids are listed below:

V = 1437.333 cm³
V = 75,398 km³
V = 59.2 ft³
V = 393.3 yd³
V = 1134.116 m³
V = 403.333 mm³
V = 405.6 in³
V = 886.808 ft³

<h3>How to determine the volume of a pyramid</h3>

Volume is the space occuppied by an object. In this question we must determine the volumes of pyramids of circular base and polygonal base (V). All the formulas needed are described below:

<h3>Volume of the pyramid</h3>

V = (π/3) · B · h (1)

<h3>Base of the pyramid - Circle</h3>

B = (π/4) · R² (2)

<h3>Base of the pyramid - Regular polygon</h3>

B = (n · L²)/(4 · tan 0.5α) (3)

<h3>Base of the pyramid - Right triangle</h3>

B = (1/2) · b · z (4)

<h3>Base of the pyramid - Rectangle</h3>

B = b · z

Where:

R - Radius
n - Number of sides of the polygon.
l - Side length
α - Internal angle, in degree.
h - Height of the pyramid
b - Base of the right triangle/rectangle.
z - Length of the right triangle/rectangle.

Now we proceed to solve each pyramid:

1) Square, n = 4, α = 90°, L = 14 cm, h = 22 cm

B = 196 cm², V = 1437.333 cm³

2) Circle, R = 3 km, h = 8 km

B ≈ 28.274 km², V = 75,398 km³

3) Right triangle, b = 12 ft, z = 3.7 ft, h = 8 ft

B = 22.2 ft², V = 59.2 ft³

4) Rectangle, b = 23 yd, z = 9 yd, h = 5.7 yd

B = 207 yd², V = 393.3 yd³

5) Circle, R = 9.5 m, h = 12 m

B ≈ 283.529 m², V = 1134.116 m³

6) Regular pentagon, B = 110 mm², h = 11 mm

V = 403.333 mm³

7) Square,n = 4, α = 90°, L = 13 in, h = 7.2 in

B = 169 in², V = 405.6 in³

8) Regular triangle, n = 3, α = 120°, L = 16 ft, h = 24 ft

B ≈ 110.851 ft², V = 886.808 ft³

To learn more on volumes, we kindly invite to check this verified question: brainly.com/question/1578538

7 0

2 years ago

Can anyone please help I am struggling with math and Noone wants to help me and I want to learn so does anyone understand HOW u

vlada-n [284]

Answer:

Step-by-step explanation:

256 = 16×16=4×4×4×4 = 4^4

X^4-4^4 = (x^2)^2 - (4^2)^2

Using algebraic identity a^2-b^2 = (a+b)(a-b)

We get (x^2+4^2)(x^2-4^2)

(x^2+4^2)(x+2)(x-2)

4 0

3 years ago

What is the slope of the line that passes through (-3, 4) and (6,-2)

Andre45 [30]

Answer:

-2/3

Step-by-step explanation:

To find the slope of the line connecting two points, divide the change in y by the change in x.

Change in y --> 4 - (-2) = 6

Change in x --> -3 - 6 = -9

Change in y ÷ change in x = 6 ÷ (-9) = -2/3

Slope = -2/3

6 0

2 years ago

Given: MNOK is a trapezoid, MN=OK, m∠M=60°, NK ⊥ MN , MK=16cm Find: The midsegment of MNOK

Sergeu [11.5K]

Answer:

12 cm

Step-by-step explanation:

1. Consider right triangle MNK. In this triangle angle N is right and m∠M=60°, then m∠K=30°. Thus, this triangle is special 30°-60°-90° right triangle with legs MN and NK and hypotenuse MK=16 cm. The leg MN is opposite to the angle with measure of 30°, then this leg is half of the hypotenuse, MN=8 cm.

2. Consider right triangle MNH, where NH is the height of trapezoid drawn from the point N. In this triangle m∠M=60°, angle H is right, then m∠N=30°. Similarly, the leg MH is half of the hypotenuse MN, MH=4 cm.

3. Trapezoid MNOK is isosceles, because MN=OK=8 cm. This means that NO=MK-2MH=16-8=8 cm.

4. The midsegment of the trapezoid is

$\dfrac{MK+NO}{2}=\dfrac{16+8}{2}=12\ cm.$

4 0

3 years ago