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Mkey [24]
3 years ago
12

New to Geometry! Help me pls!

Mathematics
2 answers:
levacccp [35]3 years ago
8 0

Answer:

19

Step-by-step explanation:

To do this problem, draw the lengths that are already given. I have done this for you, which you can see in the image below.

Subtract:

30 - 11 = 19

FG = 19

Hope this helped.

hammer [34]3 years ago
3 0

Answer:

19

Step-by-step explanation:

30 - 11 = 19

Hope that helps! Good luck!

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PLEASE HELP SOLVE THIS!!!!!!!!!!!
Sphinxa [80]

9514 1404 393

Answer:

  a) yes; 12/15/17 ~ 20/25/x; SAS

  b) x = 28 1/3

Step-by-step explanation:

The left-side segments are in the ratio ...

  top : bottom = 12 : 8 = 3 : 2

The right side segments are in the ratio ...

  top : bottom = 15 : 10 = 3 : 2

These are the same ratio, and the angle at the peak is the same in both triangles, so the triangles are similar by the SAS postulate.

Normally, a similarity statement would identify the triangles by the labels on their vertices. Here, there are no such labels, so we choose to write the statement in terms of the side lengths, shortest to longest:

  12/15/17 ~ 20/25/x

__

The sides of similar triangles are proportional, so the ratio of longest to shortest sides will be the same in the two triangles. In the smaller triangle, the longest side is 17/12 times the length of the shortest side. The value of x will be 17/12 times the length of the shortest side in the larger triangle:

  x = 17/12 · 20 = 340/12

  x = 28 1/3

4 0
4 years ago
Can someone write problems that have only neagitive numbers
rosijanka [135]

Answer:

-1822-1233

-2183*-10

-(-10)

Step-by-step explanation:

Hope it helps

5 0
3 years ago
Read 2 more answers
NEED HELP!! 30 POINTS! HAS TO BE CORRECT AND NEED THE ANSWER NOOW!
jenyasd209 [6]

Answer: options b and c

<u>Step-by-step explanation:</u>

∠ACD is supplementary to ∠ACE  <em>given</em>

∠ACD is supplementary to ∠BCD   <em>given</em>

⇒ ∠ACE is supplementary to ∠BCD   <em>transitive property</em>


∠ACD ≅ ∠BCE   <em>given</em>

⇒ ∠BCE is supplementary to ∠ACE  <em>substitution</em>

and ∠BCE is supplementary to ∠BCD   <em>substitution</em>

********************************************************************************

multiple choice options:

a) ∠ACE is supplementary to ∠BCD    <em>False</em>

b) ∠BCE is supplementary to ∠ACE    <em>TRUE</em>

c) ∠BCD is supplementary to ∠BCE    <em>TRUE</em>

d) ∠ACE ≅ ∠BCE                                   <em> False</em>

e) ∠BCD ≅ ∠ACE                                   <em>False</em>


6 0
3 years ago
10m3 of air weigh 13 kg. Chapter Reference c How much does the air weigh in a room 4.2m long, 3.5m wide, and 2.6m high?
Zarrin [17]

Answer:

The air weight in a room is 49.69 kg.

Step-by-step explanation:

It is given that the room is 4.2m long, 3.5m wide, and 2.6m high. It is also given that 10 m³ of air weigh 13 kg.

The formula to find the volume of cuboid is,

V=l\times b\times h

V=4.2\times 3.5\times 2.6

V=38.22

The volume of room is 38.22 m³.

Since it is given that, 10 m³ of air weigh 13 kg. So,

1 m^3=\frac{13}{10}kg

1 m^3=1.3kg

So the air weight in the room is,

\text{Air weight}=1.3\times 38.22

\text{Air weight}=49.686\approx 49.69

Therefore the air weight in a room is 49.69 kg.

5 0
3 years ago
Which of the following is a true statement?
aev [14]

Answer:

13/15 > 4/5 is a true stament.

Step-by-step explanation:

The left side is 0.86 repeating turned into a decimal. which means 0.86 is greater than the right which the right is 0.8 turned into a decimal. which in this case this means that the given stament is always true.

4 0
3 years ago
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