Hello,
2 cases:
if 1/3*q-5>0 then
|1/3*q-5|=1/3*q-5
1-|1/3*q-5|=-6
1-(1/3*q-5)=-6
1-1/3*q+5=-6
6-1/3*q=-6
-1/3*q=-12
q=36
else
|1/3*q-5|=-(1/3*q-5)
1-|1/3*q-5|=-6
1+(1/3*q-5)=-6
1+1/3*q-5=-6
-4+1/3*q=-6
1/3*q=-2
q=-6
Answer:
2 7/10
Step-by-step explanation:
To find difference we subtract.
3 2/5 - 7/10 = 2 7/10
The answer is 2 7/10. Please mark brainliest if possible.
Answer:
See Explanation
Step-by-step explanation:
According to the Question,
- Given That, ∠T and ∠S are complementary & ∠S and ∠U are complementary
Thus, m∠T + m∠S = 90 ------ Equation 1
& m∠S + m∠U = 90 ------- Equation 2
- Now, Subtract Equation 2 From Equation 1, we get
m∠T - m∠U = 0
Thus, m∠T = m∠U
The measure of angle T is equal to angle U.(∠U≅∠T).
Add 2 to both sides...x>3
4/(x+1) = 3/x + 1/15
Should we make common denominators with everything, we get
4*15*x / [15x(x+1)] = 3*15*(x+1)/[15x(x+1)] + x(x+1)/[15x(x+1)]
Multiply both sides of the equation by the denominator to cancel them
60x = 45(x+1) + x(x+1)
60x = 45x + 45 + x^2 + x
x^2 - 14x + 45 = 0
(x-9)(x-5) = 0
The answer to this question is that the solutions are x=9 and x=5.
