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3 years ago

If a gardener can mow a lawn in 40 min, what portion of the lawn can the gardener mow in 1 min?

Mathematics

1 answer:

Olenka [21]3 years ago

5 0

If a gardener can mow the entire lawn in 40 minutes. In 1 minute he will only be able to mow a 40th part of the lawn.

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Can somebody help me with these, i will mark you brainliest :)

Diano4ka-milaya [45]

Answer:

11 is b

Step-by-step explanation:

thats all i can do sorry

6 0

2 years ago

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all shoes are 1/7 off of the original price. how much would a pair of shoes cost that were originally $35.00

yanalaym [24]

Answer:

35 diveded by 7=5 so 35 minus 5 = 30 so the shoes are 30.00

Step-by-step explanation:

4 0

2 years ago

Solve for x.<br> Your answer must be simplified.<br> 17r > -17

Snowcat [4.5K]

Hello :D

Answer:

$\boxed{R>-1}$

The answer should have a negative sign.

Step-by-step explanation:

First, you do is divide by 17 from both sides of an equation.

$\frac{17r}{17}>\frac{-17}{17}$

Then, you simplify and solve to find the answer.

$-17\div17=-1$

$\boxed{R>-1}$ , which is our answer.

I hope this helps you!

Have a great day! :D

4 0

2 years ago

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Write an expression that represents the area of the rectangle. Remember A = LW

Iteru [2.4K]

Answer:

b) 9x² - 3x

Step-by-step explanation:

Area of a rectangle = Length × Width

Area for the rectangle = 3x - 1 × 3x

Area = $(3x-1)(3x)$

Step 1. Multiply by combining like terms

3x · 3x = 9x²

Step 2. Multiply -1 by 3x

-1 · 3x = -3x

Step 3. Combine 9x² and -3x

9x² - 3x

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doomdabomb: All brainliest and thanks are appreciated

and would mean a lot to me, thanks!

6 0

3 years ago

Boyle’s law states that the volume of a gas varies inversely with applied pressure. Suppose the pressure on 60 cubic meters of g

tatyana61 [14]

$\bf \qquad \qquad \textit{inverse proportional variation}
\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\textit{the volume of a gas varies inversely with applied pressure}}{v=\cfrac{k}{p}}
\\\\\\
\textit{we also know that }
\begin{cases}
v=60\\
p=1
\end{cases}\implies 60=\cfrac{k}{1}\implies 60=k
\\\\\\
\boxed{v=\cfrac{60}{p}}
\\\\\\
\stackrel{\textit{now if we apply 3 atmospheres, p=3, what is \underline{v}?}}{v=\cfrac{60}{3}}$

8 0

3 years ago

Read 2 more answers