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pantera1 [17]
2 years ago
6

Please help ASAP or ill fail i already am

Mathematics
2 answers:
kolezko [41]2 years ago
7 0
Are B and C the same? They look practically the same, but if you have to guess between to identical answers I say B
Bess [88]2 years ago
7 0

Answer:

the answer is C

Step-by-step explanation:

8.000 ÷ 15 = .533333333
.5333333 as a fraction is
8/15

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Help me answer this question please
Klio2033 [76]

Answer:

The answer is C.

Step-by-step explanation:

Just go to Desmos.com and plug it in.

7 0
4 years ago
Read 2 more answers
The height of a triangle is 4 inches greater than the base. The area of the triangle is 70 square inches.
Alexxandr [17]

Answer: 10 inches.

Step-by-step explanation:

We have to solve a system of equations.

The formula to calculate a triangle area is A = (b.h)/2

where b is the base and h is the height. This will be our first equation.

Since the height is 4 inches greater than the base, the second equation will be: h = b+4

We replace h and the value of the area (70 square inches) in the first equation, and we solve it by using the cuadratic equation formula:

70 = (b . (b+4)) / 2

70 . 2 = b² + 4b

140 = b² +4b

0 = b² + 4b - 140

The roots of this polynomial are -14 and 10. Since a distance can't be negative, the length of the base is 10 inches.

5 0
4 years ago
A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

Since, the function f(g(x)) is not defined for x=0.

Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



8 0
4 years ago
Is 5 a solution to the equation 3(x+1)=7(x-2)-3
salantis [7]

Answer:

yes

Step-by-step explanation:

3x5=15

3x1=3   15+3=18

7x5=35

7x2=14   35-14=21    21-3=18

18=18

6 0
3 years ago
Read 2 more answers
Make a sketch of the region and its bounding curves. Find the area of the region. The region inside one leaf of r
Anastaziya [24]

The region inside one leaf of r the area of the region is pi.20.

r =cos5θ

cos5θ =0

5θ=pi/2 ,5θ=3pi/2

θ=pi/10,θ=3pi/10

area of one leaf = ∫[pi/10 to 3pi/10](1/2)r2dθ

= ∫[pi/10 to 3pi/10](1/2)(cos5θ)2dθ

= ∫[pi/10 to 3pi/10](1/4)(1+cos10θ)dθ

=[pi/10 to 3pi/10](1/4)(θ+ (1/10)sin10θ)

=(1/4)((3pi/10)+ (1/10)sin3pi) -(1/4)((pi/10)+ (1/10)sinpi)

=(1/4)(3pi/10)  -(1/4)(pi/10)

=(1/4)(2pi/10)  

=pi/20

area of one leaf =pi.20.

Region area (calculus) Region area. The non-negative function given by y = f(x) represents a smooth curve on the closed interval [a, b].The area through the curve of f(x), the x-axis, and the perpendicular lines x = a and x = b The bounding region shown in Figure 1 is given by.

Learn more about the area of the region here: brainly.com/question/19053586

#SPJ4

4 0
1 year ago
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