Answer:
563.64 m
Explanation:
Given that as per the question
x = 5 cm = 0.05 m
D = 4.2 × 107 m
d = smallest aperture size
As per the situation the solution of the smallest aperture telescope that she can get away with is below :-
We will use Rayleigh's diffraction limit which is
The equation will be
d = 563.64 m
So, the answer is d = 563.64 m
Air pollution. Specifically the compounds sulfur dioxide and nitrogen oxide released from the burning of fossil fuels (source of air pollution), can find their way high into the atmosphere, where the compounds mix with with water, oxygen, and other chemicals to form more acidic pollutants (acid rain).
Answer:
Explanation:
Charge of particle = q
The particles have same charge
r = Distance between charge
k = Coulomb constant =
m = Mass of particle = 10 mg
g = Acceleration due to gravity = 9.81 m/s²
Electrostatic force is given by
According to Newton's second law
Here, both the electrostatic and inertial force is conserved
The charge of the particles is
The charge of the particles is very low as compared to typical static electricity
<h2>v = 2.5J/c</h2>
Explanation:
<h2>Given:</h2>
<h3>Energy = E = 20J</h3>
<h3>Charge = Q = 8C</h3>
<h2>Require :</h2>
___________
<h3>Potential Difference = V = ?</h3>
<h2>Formula :</h2>
____________
<h2>V =
</h2>
<h2>Solution:</h2><h3>_________</h3>
<h2>V =
</h2>
<h3>V = 2.5V</h3>
.
.
.
<h2>
</h2>
Answer:
- the Thevenin equivalent circuit for the battery is uploaded below
- the battery delivered 117 watts of power to the starter motor
Explanation:
Given the data in the equation
diagram of the Thevenin equivalent circuit for the battery is uploaded below.
Current I = 10 A
Voltage 1 = 12 V
voltage 2 = 11.7 v
R = (V1 - V2) / I
R = (12-11.7)/10
R = 0.3 / 10
R = 0.03Ω
Thevenin equivalent circuit
= V2 / I = 11.7 / 10
= 1.17Ω
so, power delivered to the starter motor will be;
p = (V2)² /
P = ( 11.7 V )² / 1.17Ω
p = 136.89 / 1.17
p = 117 watts
Therefore, the battery delivered 117 watts of power to the starter motor