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maksim [4K]
3 years ago
5

g A circular loop of wire with radius 3 m is flat on the xy plane in a magnetic field which is pointed in the z-direction and ha

s a magnitude of 5 μT. What is the magnitude of the induced emf in the loop if the loop shrinks to a radius of 1.5 m in 3 seconds?
Physics
1 answer:
Phantasy [73]3 years ago
7 0

Answer:

emf=-0.035V

Explanation:

this problem can be solved with the Lenz's law:

emf=-\frac{\Delta \Phi_{B}}{\Delta t}

where PhiB is the magnetic flux. In this case we have

\Delta \Phi_{B}=B(A_1-A_2)

due to the magnetic field is constant. A is the area of the circular loop. Hence

\Delta \Phi_{B}=(5*10^{-3}T)(\pi(3m)^2-\pi(1.5m)^2)=0.106Tm^2

Finally

emf=-\frac{0.106Tm^2}{3s}=-0.035V

HOPE THIS HELPS!!

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