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Crazy boy [7]
2 years ago
6

Which expression is equivalent to (5x + 2) + (4x - 3)?

Mathematics
1 answer:
mamaluj [8]2 years ago
7 0
The answer to this is E
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.Sammie paid $249.99 for a game system and then bought two equally-priced games. If she spent a total of $339.97, what is the pr
bulgar [2K]

Answer: $44.99

Step-by-step explanation:

Let P = equal prices games

The equation would be

249.99+2p=339.97

Subtract 249.99 from each side

2p=339.97

Divide by two and you got the answer.

6 0
2 years ago
When u = −2 5 , v = −5 2 , then the vectors in span{u, v} lie on a line through the origin. True or false?
Ira Lisetskai [31]

True.

The vectors are -25 in the left direction and;

-52 in the left direction

So they lie on the same line.

5 0
3 years ago
Blood pressure: High blood pressure has been identified as a risk factor for heart attacks and strokes. The proportion of U.S. a
Y_Kistochka [10]

Answer:

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

For this case we know this:

n=37 ,  p=0.2

We can find the standard error like this:

SE = \sqrt{\frac{\hat p (1-\hat p)}{n}}= \sqrt{\frac{0.2*0.8}{37}}= 0.0658

So then our random variable can be described as:

p \sim N(0.2, 0.0658)

Let's suppose that the question on this case is find the probability that the population proportion would be higher than 0.4:

P(p>0.4)

We can use the z score given by:

z = \frac{p -\mu_p}{SE_p}

And using this we got this:

P(p>0.4) = 1-P(z< \frac{0.4-0.2}{0.0658}) = 1-P(z

And we can find this probability using the Ti 84 on this way:

2nd> VARS> DISTR > normalcdf

And the code that we need to use for this case would be:

1-normalcdf(-1000, 3.04; 0;1)

Or equivalently we can use:

1-normalcdf(-1000, 0.4; 0.2;0.0658)

Step-by-step explanation:

We need to check if we can use the normal approximation:

np = 37 *0.2 = 7.4 \geq 5

n(1-p) = 37*0.8 = 29.6\geq 5

We assume independence on each event and a random sampling method so we can conclude that we can use the normal approximation and then ,the population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

For this case we know this:

n=37 ,  p=0.2

We can find the standard error like this:

SE = \sqrt{\frac{\hat p (1-\hat p)}{n}}= \sqrt{\frac{0.2*0.8}{37}}= 0.0658

So then our random variable can be described as:

p \sim N(0.2, 0.0658)

Let's suppose that the question on this case is find the probability that the population proportion would be higher than 0.4:

P(p>0.4)

We can use the z score given by:

z = \frac{p -\mu_p}{SE_p}

And using this we got this:

P(p>0.4) = 1-P(z< \frac{0.4-0.2}{0.0658}) = 1-P(z

And we can find this probability using the Ti 84 on this way:

2nd> VARS> DISTR > normalcdf

And the code that we need to use for this case would be:

1-normalcdf(-1000, 3.04; 0;1)

Or equivalently we can use:

1-normalcdf(-1000, 0.4; 0.2;0.0658)

7 0
3 years ago
Please help :( I will give u points
gayaneshka [121]

when there is no number with redical sign here it is equivalent to the exponent " 1/2 "

but when it is 3 under redical x that means it is x^1/3

In first one 8 ^(9/2) is same as ( redical 8 ) ^9

In part B it is (3 under redical 125)^9 = ( 125 )^ 9/3 so this also same thing

In part C it is ( 12)^2/7) but the ( redical 12 ) ^7 is equal to ( 12)^7/2 so these two are not equivalent

in part D it is 4^1/5 but ( redical 4) ^5 = 4^( 5/2 which is also not equivalent

Answer : only A and B are equivalent

3 0
3 years ago
Determine the intercepts of the line.<br> y = -32 + 12<br> Y-<br> X-
Lelu [443]

Answer:

y = − 20

x = none

Step-by-step explanation:

There is no X intercepts

-32 + 12 = 20

7 0
3 years ago
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