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3 years ago

Evaluate 3a2 + 4b2 for a = 2 and b = 3. O 168 48 O 36

Mathematics

2 answers:

Juliette [100K]3 years ago

8 0

Answer:

Step-by-step explanation:

a=2

b=3

3a^2+4b^2

3(2)^2+4(3)^2

3(2)(2)+4(3)(3)

3(4)+4(9)

12+36

Hope this helps ;) ❤❤❤

podryga [215]3 years ago

7 0

48 done hope this helps

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sleet_krkn [62]

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3 years ago

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nadezda [96]

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2 years ago

Use the method of elimination to determine whether the given linear system is consistent or inconsistent. If it is consistent, f

S_A_V [24]

Answer:

Step-by-step explanation:

From the given information;

We will realize that in the 2nd & 3rd equation, the integer "x" is missing.

So, the correct equation should be:

4x - 2 + 6z = 0

x - y - z = 0

2x - y + 3z = 0

By rearrangement; if we switch equation (1) and (2)

x - y - z = 0 ----- (1)

4x - 2 + 6z = 0 ------ (2)

2x - y + 3z = 0 ------ (3)

If we multiply equation (1) and add that to equation (2);

Then, we have:

x - y - z = 0

2y + 10z = 0

2x - y + 3z = 0

Also, if we multiply equation (1) by -2 and add that to equation (3), we have:

x - y - z = 0

2y + 10z = 0

y + 5z = 0

From above recent equation, if we swap equation (2) and (3);

x - y - z = 0

y + 5z = 0

2y + 10z = 0

Then, multiply equation (2) with -2, followed by adding it to equation(3);

Then:

x - y - z = 0

y + 5z = 0

0 = 0

Now, there exists no equation (3). Thus, let assume z = t to solve for x & y

y + 5z = 0

y = -5t

Similarly;

x - y - z = 0

x = -5t + t

x = -4t

Hence;

x = -4t; y = -5t; & z = t

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3 years ago

About 11% of adult Americans are left-handed. Suppose that two people are randomly selected from this

marshall27 [118]

Answer:

a) $P(X=0)=(2C0)(0.11)^0 (1-0.11)^{2-0}=0.7921$

$P(X=1)=(2C1)(0.11)^1 (1-0.11)^{2-1}=0.1958$

$P(X=2)=(2C2)(0.11)^2 (1-0.11)^{2-2}=0.0121$

And then we have our probability distribution like this:

X | 0 | 1 | 2 |

P(X) | 0.7921 | 0.1958 | 0.0121|

b) $P(X \geq 1) = P(X=1)+P(X=2) = 0.1958+0.0121=0.2079$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=20, p=0.48)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution for the problem

Part a

On this case since we select a sample size of n =2 we have the following values for the number of left handed X=0,1,2. We can find the probabilities for each case since we know that p=0.11.

$P(X=0)=(2C0)(0.11)^0 (1-0.11)^{2-0}=0.7921$

$P(X=1)=(2C1)(0.11)^1 (1-0.11)^{2-1}=0.1958$

$P(X=2)=(2C2)(0.11)^2 (1-0.11)^{2-2}=0.0121$

And then we have our probability distribution like this:

X | 0 | 1 | 2 |

P(X) | 0.7921 | 0.1958 | 0.0121|

Part b

For this case we want this probability:

$P(X \geq 1) = P(X=1)+P(X=2) = 0.1958+0.0121=0.2079$

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3 years ago

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Answer:

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Step-by-step explanation:

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