Answer:
The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.
Step-by-step explanation:
The three different assembly lines are: A₁, A₂ and A₃.
Denote <em>R</em> as the event that a component needs rework.
It is given that:

Compute the probability that a randomly selected component needs rework as follows:

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.
Answer:
Step-by-step explanation:
3x - 3y = 3(x-y)
This isnt something I can do... But draw and label a tape diagram that goes from 0 to 30.
His score is 50
How to:
First test grade:0
Second test grade:50
Third test grade: 100
Add all three and divide by 3
I can use the angle and the length of JH to find the length of IJ.
To do this, I look at the relationship IJ and JH have to the 52 degree angle. JH is opposite to angle I, and IJ is adjacent to angle I. Because the two side lengths are opposite and adjacent, I use the tangent function to solve this.
Tangent of an angle = the length of the opposite side / the length of the adjacent side. This is just another way to say tan(x)=opposite/adjacent
Now I can fill in what I know...
tan(52)=4.2/x
Now, I want to isolate x.
tan(52) = 4.2/x
x(tan(52))=4.2
x=4.2/tan(52)
Now I put 4.2/tan(52) into a calculator and get x = 3.3 ft
Hope this helps!