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shusha [124]
2 years ago
9

Using Cramer’s rule, what is the value of x in the solution to the system of linear equations below?

Mathematics
1 answer:
Aloiza [94]2 years ago
6 0

9514 1404 393

Answer:

  d  2

Step-by-step explanation:

The system of equations can be written in augmented matrix form as ...

  \displaystyle\left[\begin{array}{cc|c}-\frac{1}{2}&3&-4\\-1&-1&-1\end{array}\right]

The value of x found by Cramer's rule is the ratio of two determinants. The numerator is the coefficient matrix with the x-column replaced by the constant column. The denominator is the coefficient matrix.

  \displaystyle x=\frac{\left|\begin{array}{cc}-4&3\\-1&-1\end{array}\right| }{\left|\begin{array}{cc}-\frac{1}{2}&3\\-1&-1\end{array}\right|}=\frac{(-4)(-1)-(-1)(3)}{(-\frac{1}{2})(-1)-(-1)(3)}=\frac{4+3}{\frac{1}{2}+3}\\\\\boxed{x=2}

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The value of x after solution of the equation 8x = -16 is -2 and it is not possible to solve this equation using multiplication.

According to the question,

We have the following equation:

8x = -16

Now, this equation can not be solved using multiplication because 8 is already in multiplication with x on the left hand side. If 8 would have been in division then it could be solved using multiplication.

So, dividing by 8 on both the sides:

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Step-by-step explanation:

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