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Advocard [28]
3 years ago
13

Out of 16 spins, a purple and red spinner landed on purple 9 times and on red 7 times. Based on the experimental probability, ho

w many of the next 64 spins would you expect to land on red?
A. 28
B. 29
C. 30
D. 36


Part B

What is the probability of landing on purple select all that apply.

A. 6/16
B. 9/16
C. 0.56
D. 16/3
Mathematics
1 answer:
Nikitich [7]3 years ago
5 0

Answer:

Part A   Answer = A=28

Part B Answer is B = 9/16 + C =0.56

Step-by-step explanation:

1 = A. 28   This is because the percentage rate works out at 43.75%

2. 9/16 also, 0.56  This is because 9/16 has decimal 0.56 we can work this out by looking at the inverse of 1 ; 1= 16 16/9 = 1.77/3.17 which adds to 4.94 = 10 x 0.49  4 representing 4 from 20 =16 and 9 representing the proportion.

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Olivia flips a two-sided counter and then spins a spinner with six equal-size sections labeled 1 through 6. One side of the coun
Novay_Z [31]

Answer:

12

Step-by-step explanation:

A 2 - sided counter ; (red, yellow)

A spinner (1,2,3,4,5,6)

Number of trials = 80

P(red and number > 3) :

P(red) = 1/2 ;

P(number >3) : numbers greater Than 3 = (4, 5, 6)

Hence, P(number <3) = 3 /6 = 1/2

Theoretical probability = 1/2 *1/2 = 1/4

Expected number of outcomes :

1/4 * number of trials

1/4 * 80 = 20

Experimental outcome :

Relative frequency = number of outcomes / number of trials

Relative frequency = 2/5

Hence,

2/5 = number of outcomes / 80

Cross multiply :

160 = number of outcomes * 5

Number of outcomes = 160 /5 = 32

Actual outcomes = 32

Difference between actual and expected :

32 - 20 = 12

7 0
3 years ago
Is 300 greater than 1/2?
seropon [69]

Answer:

yes

Step-by-step explanation:

1/2 is half of 1.

300 is 300 times greater than 1, so 300 is 600 times greater than 1/2.

7 0
2 years ago
Read 2 more answers
Can somebody prove this mathmatical induction?
Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

3 step:

Check for n=k+1 whether the statement

\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)

is true.

Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

According to the 2nd step,

\sum \limits_{j=1}^k2^j=2(2^k-1)

Substitute it into the \ast

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

So, you have proved the initial statement

4 0
3 years ago
The quadratic function h(t)=-16.1t^2 + 150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15
zzz [600]
In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05 
4 0
3 years ago
Solve for x. 2(2-x) + 12x =44
Nataly [62]

Answer:

2(2-x)+12x=44

4-2x+12x=44

-4             -4

-2x +12x = 40

10x=40

/10   /10

x=4

Step-by-step explanation:

first you multiply the (2-x) by 2, you then subtract the 4 from both sides of the equation, you end up with -2x +12x = 40. Then subtract the 2x from the 12x and you end up with 10x. so now 10x=40. You then divide both sides by 10 and end up with x=10

sorry im not to good at explaining haha

8 0
2 years ago
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