The quadratic function h(t)=-16.1t^2 + 150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15
story building. - From what height, in feet, was the ball dropped?
-After how many seconds, rounded to the nearest hundredth, did the ball hit the ground?
In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
How I got that? well I was taught that if the number is 5 or higher you should round it off to the left by 1... I basically just ad a 1 to the 15 because the 6 was higher than 5 so I got 15,680 - 16,000.
