Answer:
x = 8 and y = 10
Step-by-step explanation:
Since the figures are congruent:
Angle PQR = EFG
6y + x = 68
Segment QR = FG
2x - 4 = 12
Solving that:
2x - 4 = 12
2x = 16
x = 8
Replacing x in 6y + x =68
6y + 8 = 68
6y = 60
y = 10
We have been given that a right △ABC is inscribed in circle k(O, r).
m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.
First of all, we will draw a diagram that represent the given scenario.
We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.
We will use sine to find side AB.






Wee know that radius is half the diameter, so radius of given circle would be half of the 36 that is
.
Therefore, the radius of given circle would be 18 cm.
Answer:
m∠8 = 49°
Step-by-step explanation:
∠7 and ∠8 are same-side interior angles.
Remember, same-side interior angles are supplementary. This means that the sum of the angles is 180°.
Let's use the variable 'x' to represent the unknown measure of angle ∠8.

(cancels itself out)


Therefore, the measure of ∠8 is 49°.