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Radda [10]
3 years ago
15

A rectangular prism has a length of 6 cm, a width of 3 cm, and a height of 412 cm. The prism is filled with cubes that have edge

lengths of 12 cm. How many cubes are needed to fill the rectangular prism? Enter your answer in the box. To fill the rectangular prism,( )cubes are needed.
Mathematics
2 answers:
mamaluj [8]3 years ago
3 0
1st you must find the volume of the box. Length times width time height. 6×3×412= 7416. Then you would do 7416 ÷ 12 = 618 cubes.
zubka84 [21]3 years ago
3 0

Answer:

The correct answer is 648 I just took the test.

Step-by-step explanation:

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I would appreciate if someone could answer this question I will give a brainlist for whoever explains and answers ;)
AleksandrR [38]

Answer:

Since this is a right triangle with one angle and hypotenuse given and opposite side unknown, we can use the definition of sine to find the unknown side.

sin 17 = x/hypotenuse = x/19

x = 19sin17 = 5.6

4 0
3 years ago
please solve this and show your work, no links/ ip grabbers PLEASE i’ve been asking this forever i just need the answer
Lady bird [3.3K]
19x-15 = 15x -7
4x = 8
x =2
19(2) -15 = 23
15(2) -7 = 23
6 0
2 years ago
Gaira was asked to evaluate the algebraicexpression –3.8x + 6 when x = –7.5.
icang [17]

gaira ALSO multiplied 6 by x, when 6 doesnt have 6x.

so the correct answer would be only -3.8(-7.5) + 6 which is 34.5.

5 0
3 years ago
Read 2 more answers
You buy 3.18 pounds of peaches, 1.45 pounds of oranges, and 1.78 pounds of apples. What is your total cost?
Stels [109]

Answer:6.41

Step-by-step explanation:

3.18

+1.45

1.78

=6.41

3 0
2 years ago
For which value(s) of x will the rational expression below equal zero? Check all that apply.
Ivahew [28]

Answer: D.-6 and F.3

Step-by-step explanation:

The given rational number : \dfrac{(x-3)(x+6)}{(x+7)}

To find : The value of x  , where the  rational expression becomes equal zero.

Let's check all the options :

A. 7

At x= 7  , \dfrac{(7-3)(7+6)}{(7+7)}=\dfrac{26}{7}\neq0

B. -7

At x= 7 ,  \dfrac{(-7-3)(-7+6)}{(-7+7)}=\dfrac{10}{0}=\infty\neq0

C. 6

At x= 6 ,  \dfrac{(6-3)(6+6)}{(6+7)}=\dfrac{36}{13}\neq0

D. -6

At x= -6 , \dfrac{(-6-3)(-6+6)}{(-6+7)}=\dfrac{0}{1}=0

E. -3

At x= -3 ,   \dfrac{(-3-3)(-3+6)}{(-3+7)}=\dfrac{-9}{2}\neq0

F. 3

At x= 3 , \dfrac{(3-3)(3+6)}{(3+7)}=0

Thus, at x= -6 and 3 , the rational expression equals to zero .

So , the correct options are : D.-6 and F.3

8 0
3 years ago
Read 2 more answers
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