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Rufina [12.5K]
3 years ago
15

How do i find the negative exponent

Mathematics
1 answer:
sesenic [268]3 years ago
5 0

Answer:

always 1

Step-by-step explanation:


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Each section of a race is 25 mile. the race has 4 sections.
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The answer is to that is 100
25times 4
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(a) Tom says that 1/5 + 7/20 = 8/25
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numerator = top part of the fraction

denominator = bottom part of the fraction

* means multiply

a.

you can only add the numerator when the denominator is the same

cant add the denominator

denominator has to be the same

1/5 = 4/20

4/20 + 7/20 = 11/20

b.

1 7/8 = 15/8

3/4 ÷ 15/8 =

3/4 * 8/15 =

24/60 = divide both top and bottom by 12 =

2/5

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(i) 3 (a + 5b) + a (a + 4) (ii) y (10 - y) + 3 (y - 2) (iii) 2 (8a - 5b) + 3 (5a - 12) (iv) 3 (y - 3) + ( 8 - 6y + x) (v) a (a -
AveGali [126]

Answer:

3 (a + 5b) + a (a + 4)  = a^2 + 7a + 15b

y (10 - y) + 3 (y - 2)  = - y^2+13y - 6

2 (8a - 5b) + 3 (5a - 12)  = 31a -10b  - 36

3 (y - 3) + ( 8 - 6y + x) = -3y + x-1

a (a - 2b) + b (b + 2a - c) =a^2  + b^2  - bc

5 (x - y + z) + (4x + 3y) =9x - 2y +5z

Step-by-step explanation:

Solving (i):

3 (a + 5b) + a (a + 4)

Open brackets

3 (a + 5b) + a (a + 4)  = 3a + 15b + a^2 + 4a

Collect like terms

3 (a + 5b) + a (a + 4)  = a^2 + 4a+3a + 15b

3 (a + 5b) + a (a + 4)  = a^2 + 7a + 15b

Solving (ii)

y (10 - y) + 3 (y - 2)

Open bracket

y (10 - y) + 3 (y - 2)  = 10y - y^2 + 3y - 6

Collect like terms

y (10 - y) + 3 (y - 2)  = - y^2+10y  + 3y - 6

y (10 - y) + 3 (y - 2)  = - y^2+13y - 6

Solving (iii)

2 (8a - 5b) + 3 (5a - 12)

Open bracket

2 (8a - 5b) + 3 (5a - 12)  = 16a -10b + 15a - 36

Collect like terms

2 (8a - 5b) + 3 (5a - 12)  = 16a+ 15a -10b  - 36

2 (8a - 5b) + 3 (5a - 12)  = 31a -10b  - 36

Solving (iv)

3 (y - 3) + ( 8 - 6y + x)

Open bracket

3 (y - 3) + ( 8 - 6y + x) = 3y - 9 + 8 - 6y + x

Collect like terms

3 (y - 3) + ( 8 - 6y + x) = 3y  - 6y + x- 9 + 8

3 (y - 3) + ( 8 - 6y + x) = -3y + x-1

Solving (v):

a (a - 2b) + b (b + 2a - c)

Open bracket

a (a - 2b) + b (b + 2a - c) =a^2 - 2ab + b^2 + 2ab - bc

Collect like terms

a (a - 2b) + b (b + 2a - c) =a^2 + 2ab- 2ab + b^2  - bc

a (a - 2b) + b (b + 2a - c) =a^2  + b^2  - bc

Solving (vi)

5 (x - y + z) + (4x + 3y)

Open brackets

5 (x - y + z) + (4x + 3y) =5x - 5y +5z+4x +3y

Collect like terms

5 (x - y + z) + (4x + 3y) =5x +4x +3y- 5y +5z

5 (x - y + z) + (4x + 3y) =9x - 2y +5z  

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Least common multiple of 8, 12, and 30 is 2
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