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Rufina [12.5K]
3 years ago
15

How do i find the negative exponent

Mathematics
1 answer:
sesenic [268]3 years ago
5 0

Answer:

always 1

Step-by-step explanation:


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Carla is a waitress at Daybreak Diner and she earns $5 for each hour she works. Last week she earned 148 total including $68 tip
Zigmanuir [339]

Answer: 16 hours

Step-by-step explanation:

Given

Carla earns \$5 for each hour she works

Last week she earned $148 total including \$68 tip

So, the sum of hourly income and must be equal to the total money earned

Suppose she works for x hours

\Rightarrow 5x+68=148

\Rightarrow 5x=148-68\\\Rightarrow 5x=80\\\Rightarrow x=16\ \text{hours}

Thus, she works 16 hours last week

5 0
3 years ago
Points E, F, and D are located on circle C. Circle C is shown. Line segments E C and D F are radii. Lines are drawn from points
elena55 [62]

Answer:

Option (1). 34°

Step-by-step explanation:

From the figure attached, CE and CD are the radii of the circle C.

Central angle CED formed by the intercepted arc DE = 68°

Since measure of an arc = central angle formed by the intercepted arc

Therefore, m∠CED = 68°

Since m∠EFD = \frac{1}{2}(m\angle ECD) [Central angle of an intercepted arc measure  the double of the inscribed angle by the same arc]

Therefore, m∠EFD = \frac{1}{2}(68)

                               = 34°

Therefore, Option (1) 34° will be the answer.

7 0
3 years ago
Read 2 more answers
Solve 12^x^2+5x-4 = 12^2x+6
faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

                    12^{x^{2}+5 x-4}=12^{2 x+6}

Since the base on both sides as ‘12’ are the same, we can write it as

                     x^{2}+5 x-4=2 x+6

                     x^{2}+5 x-2 x-4-6=0

                     x^{2}+3 x-10=0

Often, the value of x is easiest to solve by a x^{2}+b x+c=0 by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For a x^{2}+b x+c=0, the values of x which are the solutions of the equation are given by:

                       x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Where, a = 1, b = 3 and c = -10

                       x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}

                       x=\frac{-3 \pm \sqrt{9+40}}{2}

                       x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}

So, the solutions for ‘x’ are

                       x=\frac{-3+7}{2}=\frac{4}{2}=2

                       x=\frac{-3-7}{2}=\frac{-10}{2}=-5

The solutions for ‘x’ are 2 and -5

6 0
3 years ago
Read 2 more answers
On a number line, a number, b, is located the same distance from 0 as another number, a, but in the opposite direction. The numb
sdas [7]

Answer:

b=-a

Step-by-step explanation:

8 0
3 years ago
Using the Laws of exponents, simplify the following problem.
den301095 [7]
\frac{4 {}^{4} }{ {4}^{ - 8} ({4}^{ - 14}) } = \frac{4 {}^{4} }{ {4}^{ - 22 } }

(4^4)/(4^-22)
4^(4-(-22))
4^26


Follow my Account.
7 0
3 years ago
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