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Aleks04 [339]
3 years ago
11

Help I’m timed!!! which expression can be used to convert 80 US dollars (USD) to Australian dollars (AUD)?

Mathematics
2 answers:
Brut [27]3 years ago
8 0
The Answer is the first one or a
Sunny_sXe [5.5K]3 years ago
7 0

Answer:

A

Step-by-step explanation:

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The first three terms of an arithmetic sequence are as follows
ozzi

Answer:

32 and 39

Step-by-step explanation:

The common difference d for the sequence is 7

1st term of the sequence a1 is 11.

4th (a4) and 5th  (a5) term of the sequence are required

nth term of an arithmetic sequence an =a1+(n-1)d

a4=11+(4-1)7=32

a5=11+(5-1)7=39

4 0
2 years ago
Which ordered pair is a solution to this system of equations. 7x+5y=59 and 3x-9y=159
alina1380 [7]
Your is answer should be D
7 0
3 years ago
Read 2 more answers
If the APY of a savings account is 3.9%, and if the principal in the savings account is $3700 for an entire year, what will be t
joja [24]

Answer:

Option B. \$3,844.30

Step-by-step explanation:

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=1\ years\\ P=\$3,700\\r=0.039

substitute in the formula above

A=\$3,700(1+0.039*1)=\$3,844.30

4 0
3 years ago
Read 2 more answers
Suppose the test scores on an exam show a normal distribution with a mean of 82 and a standard deviation of
Zanzabum

Answer:

a) Between 74 and 90

b) 81.86% of the scores are between 78 and 90

Step-by-step explanation:

a) According to the Empirical Rule, in a normal distribution, 95% of the data are within 2 standard deviations of the mean. Therefore, the range that 95% of the scores fall in is between 82-4(2)=74 and 82+4(2)=90.

b) The percent of scores that are between 78 and 90 is: normalcdf(lower,upper,μ,σ) = normalcdf(78,90,82,4) = 0.8185946784 ≈ 0.8186, or about 81.86% of the scores.

5 0
2 years ago
Valuate the line integral, where c is the given curve. ∫c zdx + xdy + ydz
Semenov [28]
\displaystyle\int_{\mathcal C}z\,\mathrm dx+x\,\mathrm dy+y\,\mathrm dz=\int_{\mathcal C}\langle z,x,y\rangle\cdot\mathrm d\langle x,y,z\rangle
\displaystyle=\int_{t=0}^{t=1}\langle t^2,t^2,t^3\rangle\cdot\mathrm d\langle t^2,t^3,t^2\rangle
=\displaystyle\int_0^1\langle t^2,t^2,t^3\rangle\cdot\langle2t,3t^2,2t\rangle\,\mathrm dt
=\displaystyle\int_0^15t^4+2t^3\,\mathrm dt=\frac32
3 0
3 years ago
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