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vagabundo [1.1K]
3 years ago
15

Determine the volume of the shaded region. Use the pie button on your calculator.

Mathematics
1 answer:
Mashutka [201]3 years ago
5 0

Answer:

23.89 cm^3

Step-by-step explanation:

You will need to use two volume formulas. Find the volume. Then subtract their volume to find whats left over.

1. Volume of cylinder formula- V = \pi r^{2} h

The h = 8.8 and the

The r = 1.5 (radius is half of the diameter which is 3)

Substitute the numbers into the formula

V=\pi1.5^{2}8

V= 62.2 cm

2. Volume of Sphere formula- V = \frac{4}{3} \pi  r^{3}

The r = 1.45 (radius is half of the diameter which is 2.9) (radius of the circle)

Substitute the numbers into the formula

V= \frac{4}{3}  \pi (1.45)^{3}

V= 12.77

Since there are 3 sphere's we need to multiple 12.77 * 3 = 38.31

3. Subtract the total volumes from the cylinder and the 3 sphere's

62.2 - 38.31 = 23.89

The V = 23.89

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What's the answer <br>1-(-5)
Hatshy [7]

Answer:

6

Step-by-step explanation:

since there is a parentheses in-between both subtraction sign it turns into a plus sign which would into the equation 1+5=6

8 0
3 years ago
Read 2 more answers
A ball is thrown from a height of 105 feet with an initial downward velocity of 9 ft/s. The ball's height h (in feet) after t se
zloy xaker [14]

Answer:

t = 2.28 s

Step-by-step explanation:

h = 105 - 9t - 16t ^ 2

0 ft = 105 ft - 9t -16^t

To find the roots of a quadratic function we have to use the Bhaskara formula , the roots will give us the time it takes to reach zero height

ax^2 + bx + c  = 0

-16^t - 9t + 105 ft = 0 ft

a = -16    b = -9    c = 105

t1 = (-b + √ b^2 - 4ac)/2a

t2 =(-b - √ b^2 - 4ac)/2a

t1 = (9 + √(-9^2 - (4 * (-16) * 105)))/2 * (-16)

t1 = (9 + √(-81 + 6720))/ -32

t1 = (9 + √6639)/ -32

t1 = (9 + 81.84)/ -32

t1 = 90.84 / -32

t1 = -2.83 s

t2 = (9 - √(-9^2 - (4 * (-16) * 105)))/2 * (-16)

t2 = (9 - √(-81 + 6720))/ -32

t2 = (9 - √6639)/ -32

t2 = (9 - 81.84)/ -32

t2 = -72.84 / -32

t2 = 2.28 s

we have two possible values, we are only going to take the positive one, beacause we are talking about time

t2 = 2.28 s

3 0
3 years ago
The monthly cost of driving a car depends on the number of miles driven. Lynn found that in May her driving cost was $380 for 48
andrezito [222]

Answer:

y=0.2x+284

Step-by-step explanation:

Let  x be the distance driven, d-distance and C our constant.

Our information can be presented as:

y=mx+c\\\\450=830x+C\ \ \ \ \ \ \ \ \ eqtn 1\\\\380=480x+C\ \ \ \ \ \ \ \ \ eqtn 2

#Subtracting equation 2 from 1:

70=350x\\x=0.2

Hence the fixed cost per mile driven,x is $0.20

To find the constant,C we substitute x in any of the equations:

450=830x+C\ \ \ \ \ \ \ X=0.2\\\therefore C=450-830\times0.2\\=284

Now, substituting our values in the linear equation:

y=0.2x+284       #y=cost of driving, x=distance driven

Hence the linear equation for the cost of driving is y+0.2x+284

7 0
3 years ago
LIVE
zzz [600]

Answer

Step-by-step explanation:

8 0
3 years ago
Can u help me with this
Nesterboy [21]
A graphing calculator is a great help for problems of this nature.
  x ∈ {-5.63, -0.55, 2.59}

4 0
3 years ago
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