Answer:
See below.
Step-by-step explanation:
x^2 + 2 = 3^2/3 + 3^-2/3
x^2 = 3^2/3 + 3^-2/3 - 2
x = √(3^2/3 + 3^-2/3 - 2)
x = 0.748888296
Substitute for x in 3x^3 + 9x - 8:
3( 0.748888296)^3 + 9( 0.748888296) - 8 = 0.
So it is proved.
Answer:
The smaller bottle holds 12.5 ml of perfume.
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<h2>Given</h2>
- Two bottles of similar shape;
- Larger bottle has volume of 100 ml;
- The length of larger bottle is 10 cm;
- The length of smaller bottle is 5 cm.
<h2>To find </h2>
- The volume of smaller bottle.
<h2>Solution</h2>
Find the scale factor, the ratio of corresponding dimensions:
We know the volume is the function of three dimensions, therefore the ratio of volumes is the cube of the scale factor:
Substitute the known values and find the volume of small bottle:
The smaller bottle holds 12.5 ml of perfume.
.5 as a decimal and 50% as a percent
Answer:
Look below
Step-by-step explanation:
lets have -29 be y2 and -5 be x2
21 - (-)29
5 - (-)5
Subtracting a negative is just adding it so
21 + 29 50
5 + 5 10
50/10
this simplified, is 5/1 or 5
y=5x+b
now we need to find b, so we substitute y and y
x = 5
y = 21
21=5*5=b
5*5 is 25
now we need to get to 21
25 -4 is 21
b = -4
y=5x-4
We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].
AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13
BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13
CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13
DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13
The two polygons are squares with the same side lengths.
But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions:
1. They have the same number of sides.
2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.
The third condition was not proven.
