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kondaur [170]
3 years ago
5

The graph shows point F located at (0, 6) and line d given by the equation y = 0.

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
8 0

Answer:

equidistant from point F and line d: (0, 3); (6, 6) and (-6, 6)

not equidistant from point F and line d: (3, 0); (3, 5) and (-2, 2)

Step-by-step explanation:

Point (0, 3)

Distance from point (0, 6) = 3

Distance from line d = 3

Point (6, 6)

Distance from point (0, 6) = 6

Distance from line d = 6

Point (3, 0)

Distance from point (0, 6) = √[(3 - 0)² + (0 - 6)²] = √45

Distance from line d = 0

Point (3, 5)

Distance from point (0, 6) = √[(3 - 0)² + (5 - 6)²] = √10

Distance from line d = 5

Point (-2, 2)

Distance from point (0, 6) = √[(-2 - 0)² + (2 - 6)²] = √20

Distance from line d = 2

Point (-6, 6)

Distance from point (0, 6) = 6

Distance from line d = 6

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