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3 years ago

How to solve the problem

Mathematics

1 answer:

mestny [16]3 years ago

6 0

Substitute 4 for x.
-|4-7|+3
-3+3
f(4) = 0

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I need help on this math problem!

swat32

(-7, 2) is the location of W.

because W on the X axis is -7

and W on the Y axis is 2.

making it (-7, 2)

8 0

3 years ago

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

3 years ago

The ratio of roses to carnations is 7 to 5. If 96 flowers are needed for table decorations,

coldgirl [10]

Answer: 56 roses and 40 carnations are needed.

Step-by-step explanation: Here’s the table of ratios that’ll help you find how many roses and carnations are needed to make a total of 96 flowers for table decorations:

7:5 /14:10 /21:15 /28:20 /35:25 /42:30 /49:35/ 56:40/

*56 + 40 = 96

Hence, 56 roses and 40 carnations are needed if 96 flowers are needed for table decorations.

8 0

2 years ago

The set of x valúes of a function this is another name of range

marin [14]

Answer:

False?

Step-by-step explanation:

We can't tell what the question is here, but it looks like you want to know about the definition of domain and range.

The set of x-values is the domain.

The set of y-values is the range.

"range" is not another name for the set of x-values.

8 0

3 years ago

Help me plz!

Goryan [66]

Answer:

1,451.61 cm²

Step-by-step explanation:

A = LW

A = 38.1 x 38.1 (since a checkerboard has to be square)

A = 1,451.61

8 0

3 years ago