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scoundrel [369]
3 years ago
7

What is the solution to 2x squared + 8x = x squared -16

Mathematics
2 answers:
k0ka [10]3 years ago
6 0

Answer:

x= -4

Step-by-step explanation:

subtract x² over and add 16 so that the equation is equal to 0 so you get:

x²+ 8x + 16 = 0

then factor,

(x+4)(x+4)=0

solve for x

x+4=0

x=-4

sweet [91]3 years ago
3 0

Answer:

x=-4

Step-by-step explanation:

2x^2+8x=x^2-16

2x^2+8x+16=x^2-16+16

2x^2+8x+16=x^2

2x^2+8x+16-x^2=x^2-x^2

x^2+8x+16=0

x_{1,\:2}=\frac{-8\pm \sqrt{8^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}

8^2-4\cdot \:1\cdot \:16

=8^2-64

=64-64

=0

x_{1,\:2}=\frac{-8\pm \sqrt{0}}{2\cdot \:1}

x=\frac{-8}{2\cdot \:1}

\frac{-8}{2\cdot \:1}

=\frac{-8}{2}

=-4

x=-4

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