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3 years ago

How would you use estimation to evaluate this expression 10.2 x [(2x3.7)+8]

1 answer:

6 0

Round off the decimals to a sensible number. So 3.7 would be 4 and 10.2 would be 10. In this case, it would be (2 × 4 + 8) × 10 which is 160.

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Wat is x in 1/3x - 11 = 5

kirza4 [7]

=48

Multiply by 1

Add 1 1 11 11

to both sides of the equation

6 0

3 years ago

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Seven times a number plus the number is 24. what is the number

katrin2010 [14]

Answer:

x=3 is the number

Step-by-step explanation:

Suppose number be "x".

Equation will be

7x + x = 24

8x = 24

x = 24/8

x = 3

5 0

3 years ago

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Can anyone help me with this equation 19 + 19 equals X ???

dezoksy [38]

Answer:

19+19= x

So x, is 38. Just add 19 and 19

8 0

3 years ago

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WILL GIVE BRAINLIEST!

jek_recluse [69]

Angle c (36 degree) is equal to angle a
Angle a=36 degree
a+b=180
b=180-36
b=144 degree
Angle b=144 degree

6 0

3 years ago

(1+tanx)/(sinx+cosx)=secx

jek_recluse [69]

$\frac{1+\tan x}{\sin x+\cos x}=\sec x$ is proved

<h3><u>Solution:</u></h3>

Given that,

$\frac{1+\tan x}{\sin x+\cos x}=\sec x$ ------- (1)

First we will simplify the LHS and then compare it with RHS

$\text { L. H.S }=\frac{1+\tan x}{\sin x+\cos x}$ ------ (2)

$\text {We know that } \tan x=\frac{\sin x}{\cos x}$

Substitute this in eqn (2)

$=\frac{1+\frac{\sin x}{\cos x}}{\sin x+\cos x}$

On simplification we get,

$=\frac{\frac{\sin x+\cos x}{\cos x}}{\sin x+\cos x}$

$=\frac{\sin x+\cos x}{\cos x} \times \frac{1}{\sin x+\cos x}$

Cancelling the common terms (sinx + cosx)

$=\frac{1}{c o s x}$

We know secant is inverse of cosine

$=\sec x=R . H . S$

Thus L.H.S = R.H.S

$\frac{1+\tan x}{\sin x+\cos x}=\sec x$

Hence proved

5 0

3 years ago