Question

Ammonium phosphate is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid with liquid ammonia. Calculate the moles of phosphoric acid needed to produce of ammonium phosphate. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.

Answer 1

The given reaction is incomplete. The complete reaction is as follows.

Ammonium phosphate $[(NH_{4})_{3}PO_{4})$ is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid $H_{3}PO_{4}$ with liquid ammonia. Calculate the moles of phosphoric acid needed to produce 1.30 mol of ammonium phosphate. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.

Explanation:

Chemical equation for the given reaction is as follows.

     $H_{3}PO_{4}(aq) + 3NH_{3}(l) \rightarrow (NH_{4})_{3}PO_{4}(s)$

Therefore, moles of $H_{3}PO_{4}$ required will be calculated as follows.

         $1.30 mol \times (NH_{3})_{4}PO_{4} \times \frac{1 \text{mol} H_{3}PO_{4}}{1 \text {mol} (NH_{4})_{2}PO_{4}}$

             = 1.30 mol $H_{3}PO_{4}$

Therefore, we can conclude that the moles of phosphoric acid needed to produce 1.30 mol of ammonium phosphate are also 1.30 mol.