All categories

3 years ago

Find the density of a substance that has a mass of 75 g and a volume of 35 mL. Don't forget your units!

Chemistry

1 answer:

Andrew [12]3 years ago

5 0

Answer:

The density of a substance that has a mass of 75 g and a volume of 35 mL is 2.14 $\frac{g}{mL}$

Explanation:

Density is a characteristic property of a substance that relates to the amount of mass it has per unit volume. In other words, density is the property that matter, whether solid, liquid or gas, has to compress into a given space (it measures the amount of mass in a given volume of a substance). It is calculated as the quotient between the mass of a body and the volume it occupies:

$density=\frac{mass}{volume}$

In this case, you know:

mass= 75 g
volume= 35 mL

Replacing:

$density=\frac{75 g}{35 mL}$

Solving:

$density=2.14\frac{g}{mL}$

The density of a substance that has a mass of 75 g and a volume of 35 mL is 2.14 $\frac{g}{mL}$

You might be interested in

Write the chemical formula for the chlorite ion

Licemer1 [7]

Answer:

$cl { }^{ - }$

hope that helps uhh!!

8 0

3 years ago

Read 2 more answers

A sample that contains only SrCO3 and BaCO3 weighs 0.846 g. When it is dissolved in excess acid, 0.234 g carbon dioxide is liber

In-s [12.5K]

Answer:28.605

Explanation:First, the molar mass of of SrCO3, BaCO3 and CO2 has to be calculated, (using the molar mass of each element Sr = 87.62, Ba = 137.327, C=12.011, O= 16.00)

The molar masses are;

SrCO3 = 87.62 + 12.011 + (3*16) = 147.631g/mol

BaCO3 = 79.904 + 12.011 + (3*16) = 197.34 g/mol

CO2 = 12.011 + (2*16) = 44.011 g/mol

To obtain one of the equations to solve the problem;

The sample is made of SrCO3 and BaCO3 and has a mass of 0.846 g. Representing the mass of SrCO3 as ma and that of BaCO3 as mb. The first equation can be written as:

ma + mb = 0.846g (1)

To obtain another equation in order to be able to determine the different percentages of the compounds (SrCO3 and BaCO3) that make of the sample, a relationship can be obtained by determining the relationship between the number of moles of CO2 formed as the mass of the SrCO3 and BaCO3;

The number of moles of CO2 formed = (mass of CO2)/(molar mass) =0.234/44.011 =0.00532moles

CO2 contains 1 mole of carbon (C) so therefore 0.00532 moles of CO2 contains 0.00532 moles of C

The sample produced 0.00532 moles of CO2, therefore the number of moles SrCO3 and BaCO3 that produced this amount can be calculated using the formula;

= (mass )/(molar mass)

No of moles of SrCO3 and BaCO3 will be ma/147.631 and mb/197.34 moles respectively

The total amount of C molecules produced by SrCO3 and BaCO3 will be 0.00532 moles of C

The second equation can be written as

ma/147.631 + mb/197.34= 0.00532 (2)

Solving Equation (1) and (2) simultaneously;

ma = 0.604g; mb = 0.242g

Therefore the percentage of BaCO3 = (mass of BaCO3 )/(mass of sample )*100

= 0.242/(0.846 )*100

= 28.605%

5 0

4 years ago

Choose the CORRECT statement.

devlian [24]

Answer:

Paper has been changed chemically when it is torn into pieces.

Particles of matter move more quickly when their temperature gets cooler.

(this two are correct)

Explanation:

7 0

3 years ago

Write the chemical formulas and names for the following ionic compounds. Cobalt (III) and bromine

ahrayia [7]

Answer:

CoBr2,CoBr2·6H2O,CoBr2·2H2O

Explanation:

4 0

2 years ago

108/49 In ? 108/48 Cd + ? In the equation above, what particle or type of radiation needs to be included on the right hand side

Oksanka [162]

Answer: b) positron

Explanation:

The antiparticle or the antimatter counterpart of the electron is called positron.

The positron has an electric charge of +1 e and same mass as an electron. When a positron collides with an electron, annihilation takes place.

Below is an attachnent that further explains this

7 0

3 years ago