Answer:
b
Explanation:
<em>Let the wild type trait, the silver-white, be represented by </em><em>A</em><em> allele and the mutant trait, the golden color, be represented by </em><em>a</em><em> allele.</em>
Heterozygous wild-type male fish would be Aa
Golden female fish would be aa
Aa x aa
Aa Aa aa aa
2/4 Aa = silver-white
2/4 aa = golden color
<em>Hence, the percent likelihood of golden offspring is </em><em>2/4 or 50%.</em>
The correct option is b.
