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Ira Lisetskai [31]
3 years ago
8

A quantity a varies directly as a quantity b, if, when b changes, a changes in the same ratio. What happens to the quantity a if

the quantity b doubles in value?
Mathematics
1 answer:
drek231 [11]3 years ago
6 0
This means that if b doubles, then a will become half as large. For the inverse of the ratio 2 to 1 ("doubles") is the ratio 1 to 2 ("half"). The terms are exchanged; the inverse of the ratio a : b is the ratio b : a. When a varies inversely as b, we say that a is inversely proportional to b.
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How do you solve this system by substitution. Y= -5x+3<br> -x-7y=13
geniusboy [140]
<span>A) Y= -5x+3
B) -x -7y = 13 substituting equation A) into B)
B) -x -7*(-5x +3) = 13
</span>
<span>B) -x +35x -21 = 13
B) 34x = 34
x = 1
</span>
<span>A) Y= -5*1 +3
A) Y= -2

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3 0
3 years ago
When a particular type of thumbtack is​ dropped, it will land point up ​(A flat-top thumbtack resting on its flat top​) or point
erma4kov [3.2K]

Answer:

0.48

0.52

No

Yes

Step-by-step explanation:

Result of experiment :

Point up = 48

Point down = 52

Total number of trials = 100

Recall :

Experimental probability = number of outcomes / number of trials

1.)

P(Landing point up) = 48 / 100 = 0.48

2.)

P(Landing point down) = 52 / 100 = 0.52

3.)

The same result will not occur has the outcomes of trials aren't fixed.

4.) Yes, nearly the same result could occur on the second trial, as the number of possible outcubes are just 2 and the number if trials is high.

8 0
3 years ago
What is PEMDAS and GEMS ? <br> Pls Help ASAP :) WILL GIVE BRAINLIEST IF RIGHT !!
jolli1 [7]

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3 0
3 years ago
Read 2 more answers
Y=1/2x-1
Alinara [238K]

Answer:

<h2>Y=1/2x-1</h2>

Find where the expression

1/2x−1 is undefined.

x=1/2

Consider the rational function

R(x)=ax^n/bx^m where n is the degree of the numerator and m is the degree of the denominator.

1. If n<m, then the x-axis, y=0, is the horizontal asymptote.

2. If n=m, then the horizontal asymptote is the line y = ab.

3. If n>m, then there is no horizontal asymptote (there is an oblique asymptote).

Find n and m.n=0m=1

Since n<m, the x-axis, y=0, is the horizontal asymptote.y=0

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.

No Oblique Asymptotes

This is the set of all asymptotes.

Vertical Asymptotes:

x=1/2

Horizontal Asymptotes:

y=0

No Oblique Asymptotes

<h2>2x+y=4</h2>

Subtract 2x from both sides of the equation.

y=4−2x

Rewrite in slope-intercept form.

The slope-intercept form is

y=mx+b, where m is the slope and b is the y-intercept.

y=mx+b

Reorder 4 and −2x.

y=−2x+4

Use the slope-intercept form to find the slope and y-intercept.

Find the values of m and b using the form

y=mx+b.

m= - 2b=4

The slope of the line is the value of m, and the y-intercept is the value of b.

Slope: −2

y-intercept: (0,4)

Any line can be graphed using two points. Select two x values, and plug them into the equation to find the corresponding y

values.

Find the x-intercept.

x-intercept(s):

(2,0)

Find the y-intercept.

y-intercept(s):

(0,4)

Create a table of the x and y values.

x y

0 4

2 0

Graph the line using the slope and the y-intercept, or the points.

Slope: −2

y-intercept:

(0,4)

Step-by-step explanation:

Hope it is helpful...

8 0
3 years ago
Given (1, -3) and (5, 1). The slope of the line is The equation of the line is
guapka [62]

To find the slope of the line we can use the following formula:

\frac{y.2 - y.1}{x.2 - x.1} = m

1 - (-3)/5 - 1

4 / 4

1

<h3>The slope of the line is equal to 1.</h3>

To find the equation, we can just use slope-intercept form.

We already know the slope, so our current equation is y = x

By knowing the slope, we can apply the slope to our lowest pair of coordinates to find the y value when x = 0.

Subtract 1 from the x and y values of (1, -3)

(0, -4) is our new point, and so we know the y-intercept is -4.

<h3>Our equation for the line is y = x - 4</h3>
4 0
3 years ago
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