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Anestetic [448]
3 years ago
8

One hundred people were asked, "do you favor stronger laws on gun control?" of the 33 that answered "yes" to the question, 14 we

re male. of the 67 that answered "no" to the question, six were male. if one person is selected at random, what is the probability that this person answered "yes" or was a male? round the the nearest hundredth.
Mathematics
1 answer:
jok3333 [9.3K]3 years ago
3 0

The information we have allow us to sketch the following scenario. There are:

  • 14 males who voted yes
  • 19 females who voted yes
  • 6 males who voted no
  • 61 females who voted no

So, the statement "answer yes or be a male" covers the first three bullet points: the only part not covered by the statement is the last bullet point, because it is about females who voted no, so both conditions of the "or" statement are false.

So, out of a total of

14+19+6+61=100

people, those who answered yes or are male are

14+19+6 = 39

This means that if you pick a person at random, you have a

\dfrac{39}{100}=0.39

chance of picking someone who meets your criteria.

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Simplify (a+b)^3 + (a-b)^3 + 6a(a^2-b^2)
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Answer:

8a^3.

Step-by-step explanation:

(a+b)^3=a^3+b^3+3a^2b+3ab^2

(a-b)^3=a^3-b^3-3a^2b+3ab^2

(a+b)^3+(a-b)^3=2a^3+6ab^2

According to the question

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Put in the value

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From this statement "the area of the opening may be expressed as the function: a(θ) = 16 sin θ ⋅ (cos θ + 1).

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The area of the opening = 16 sin 30 ⋅ (cos 30 + 1)

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The graph of this function can be seen below:

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