Hello from MrBillDoesMath!
Answer:
b2 = 5
Discussion:
A = 1/2 h (b1 + b2)
.
Substituting A = 16, h = 4, and b1=3 in the above formula gives:
16 = (1/2) (4)( 3 + b2) => (as (1/2)4 = 2) )
16 = 2 ( 3 + b2) => (divide both sides by 2)
8 = (3 + b2) => (subtract 3 from both sides)
8-3 = b2 =>
5 = b2
Check Area formula:
Does A = 16 = (1/2)(4)(3+5) ?
Does 16 = (1/2) (4)(8) ?
Does 16 = (1/2)(32) ? Yes it does so our calculation for b2 is correct
Thank you,
MrB
NO.,the given measures can not be the lengths of the sides of a triangle
Step-by-step explanation
The sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
so, Find the range for the measure of the third side of a triangle given the measures of two sides.
here given measures are 2,2,6
2+2 = 4 which is less than the third side 6
= 4 < 6
This not at all a triangle.
Hence, the given measures can not be the lengths of the sides of a triangle
Step-by-step explanation:
try surfing how to divide a function by the long division method
Answer:
5-5 is 0
Step-by-step explanation:
