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2 years ago

♡please help dudes ♡

Mathematics

2 answers:

padilas [110]2 years ago

6 0

Answer:

114°

Step-by-step explanation:

<h2><u>Find the angle </u></h2>

looking at the picture we can notice that the angle are lying on the same plane and are therefore regarded as corresponding angles. this is due to the fact that they are formed when a line intersects with a pair of parallel lines.

corresponding angles mean:

<em>angle A = angle B</em>

6x + 12 =3x + 63

make x the subject of formula:

6x - 3x = 63 - 12

3x = 51

x = 51/3

<u></u>

<h3><em><u>To find the angle A </u></em></h3>

place the value of x into the equation and solve :

A = 6x + 12

= 6(17) + 12

= 114°

<h3><u>the angle A is 114°</u></h3>

<u />

dimulka [17.4K]2 years ago

5 0

Answer:

114°

Step-by-step explanation:

<A=<B (corresponding angles)

6x+12=3x+63

6x-3x=63-12

3x=51

Dividing both sides by 3

x=17

Now

<A=6x+12

=6(17)+12

=102+12

=114°

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2 years ago

during a softball game kay hit a fly ball the function f(x) = -16t^2 + 64t + 4 describes the height of the softball in feet. mak

STatiana [176]

<h2>Hello!</h2>

The graph is attached.

To graph a parabola we need to know the following:

- If the parabola is open upwards or downwards

- They axis intercepts (if they exist)

- The vertex position (point)

We are given the function:

$f(t)=-16t^{2}+64t+4$

Where,

$a=-16\\b=64\\c=4$

For this case, the coefficient of the quadratic term (a) is negative, it means that the parabola opens downwards.

Finding the axis interception points:

Making the function equal to 0, we can find the x-axis (t) intercepts, but since the equation is a function of the time, we will only consider the positive values, so:

$f(t)=-16t^{2}+64t+4\\0=-16t^{2}+64t+4\\-16t^{2}+64t+4=0$

Using the quadratic equation:

$\frac{-b+-\sqrt{b^{2}-4ac } }{2a}=\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}\\\\\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}=\frac{-64+-\sqrt{4096+256} }{-32}\\\\\frac{-64+-\sqrt{4096+256} }{-32}=\frac{-64+-(65.96) }{-32}\\\\t1=\frac{-64+(65.96) }{-32}=-0.06\\\\t2=\frac{-64-(65.96) }{-32}=4.0615$

So, at t=4.0615 the height of the softball will be 0.

Since we will work only with positive values of "x", since we are working with a function of time:

Let's start from "t" equals to 0 to "t" equals to 4.0615.

So, evaluating we have:

$f(0)=-16(0)^{2}+64(0)+4=4\\\\f(1)=-16(1)^{2}+64(1)+4=52\\\\f(2)=-16(2)^{2}+64(2)+4=68\\\\f(3)=-16(3)^{2}+64(3)+4=52\\\\f(4.061)=-16(4.0615)^{2}+64(4.0615)+4=0.0034=0$