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3 years ago

Please i need your help...Thanks

Mathematics

1 answer:

pishuonlain [190]3 years ago

8 0

Lol I’m not sure but I’m logging in so it’s making me “answer”

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G is proportional to the square of t. If t=2 and g=64, find g when t=3.5.

choli [55]

$If\ g\ is\ proportional\ to\ the\ t^2\ we\ have\ proportion\\\\
g=64\ \ \ \ ---\ \ \ t^2=2^2=4\\\\\
g=?\ \ \ ----t^2=(3,5)^ 2=12,25\\\\
4g=64*12,25\\\\
4g=784\ \ |:4\\\\g=196\\\\ Answer\ is\ g=196\ for\ t=3,5.$

4 0

3 years ago

2n + 1.6 = 17.6 what is the value of n?

Vinil7 [7]

Answer:

Step-by-step explanation:

2n + 1.6 = 17.6 what is the value of n?

2n + 1.6 = 17.6

2n = 17.6 - 1.6

2n = 16

n = 16 : 2

n = 8

-----------------

check

2n + 1.6 = 17.6

2*8+1.6=17.6

16+1.6=17.6

17.6=17.6

the answer is good

7 0

2 years ago

Read 2 more answers

Please help with question below.

Nonamiya [84]

Answer:

Step-by-step explanation:

We have to find the points that are on the graph by finding the order pair (x, y) We are given the x value, so substitute x in the given equation f(x) and find y.

The graph is a line

6 0

3 years ago

The perimeter of a rectangle is 90 cm the length is 27 cm what is the width of the rectangle

ser-zykov [4K]

Answer:

width = 18 cm

Step-by-step explanation:

perimeter of rectangle = 2(length + width)

then:

90 = 2(27+w)

90/2 = 27+w

w = width

45 = 27+w

45 - 27 = w

18 = w

Check:

90 = 2(27+18)

90 =2*45 =

3 0

3 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):