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The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at (-1.5, -3.25).
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For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at (-1.5, -3.25).
_____
For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
Step-by-step explanation:
<h2>Answer:-</h2><h3>Given ,</h3>The figure is Similar.
Observation:-
Similar figures have similar sides. If we see carefully in smaller triangle, 3 has been added to each side and they are similar. We need to find y.
We have :-
5+3=8 as similar sides.
So, applying same algorithm,
is the answer.
Hope it helps :)
The standard error of the mean is 12.
The standard error of the mean points to the standard deviation of the distribution of a sample mean obtained from a population.
The standard error S.E of the mean can be calculated by using the formula:
where;
- standard deviation
= 24
- sample size n = 4
S.E = 12
Learn more about the Standard error of the mean here: