Answer:
135 masks
Step-by-step explanation:
i hope my math is right lol
Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
Answer:
n = the first
n + 1 = the 2nd
n + 2 = the 3rd
n(n + 2) - (n + 1) = 10(n + 2) + 1
n2 + 2n - n - 1 = 10n + 20 + 1
n2 - 9n - 22 = 0
(n - 11)(n + 2) = 0
If two factors = 0, at least one must = 0.
n - 11 = 0
n = 11
11,12,13
n + 2 = 0
n = -2
-2,-1,0
She can have 7 days off at most because 3 X 1250 = 3750 - 700 = 3050
