<span>The answer is B. 72.25 percent.
The Hardy-Weinberg principle can be used:</span>
<em>p² + 2pq + q² = 1 </em>and <em>p + q = 1</em>
where <em>p</em> and <em>q</em> are the frequencies of the alleles, and <em>p²</em>, <em>q²</em> and <em>2pq</em> are the frequencies of the genotypes.
<span>The <em>p</em> allele (<em>q</em>) is found in 15% of the population:
q = 15% = 15/100
Thus, q = </span><span>0.15
To calculate the <em>P</em> allele frequency (<em>p</em>), the formula <em>p + q = 1</em> can be used:
If p + q = 1, then p = 1 - q
p = 1 - 0.15
Thus, </span><span>p = 0.85
Knowing the frequency of the <em>P</em> allele (<em>p</em>), it is easy to determine the frequency of the <em>PP </em>genotype (<em>p²</em>):
p² = 0.85² = 0.7225
Expressed in percentage, p² = 72.25%.</span>
Answer:
c. Would have deviated from the 9:3:3:1 phenotypic ratio
Explanation:
<em>If two genes are linked together on the same chromosome, the phenotype of the F2 generation would have deviated from 9:3:3:1.</em>
Two genes whose loci are close on the same chromosome are said to be linked. Linked genes have higher frequency of recombination than genes that are not linked.
<u>Hence, while genes that are not linked assort independently to produce 9:3:3:1 phenotypic ratio at F2, linked genes do not assort independently and the higher frequency of recombination ensures that they standard phenotypic ratio is deviated from.</u>
The correct option is c.
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Answer:
Are you asking what factors effect mutation rate?
If you are could you be a little more specific because technically even you just damaging tissue increases the likelihood of a mutation occurring due to mitosis occurring to repair the destroyed cells. So every time you have to replicate DNA you’re at risk an increased risk for mutation assuming it was the result of something like a cut.
sorry I have to go
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