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saw5 [17]
3 years ago
7

What inequality is equivalent to |x-4| <8?

Mathematics
1 answer:
Furkat [3]3 years ago
5 0

Answer:

x<《-4,12》

Step-by-step explanation:

inequalities:

x-4<8, x-4>0

-(x-4)<8, x-4-<0

intersections:

x<12, x>4

x>-4, x<4

x<[4,12》

x<《-4,4》

x<《-4,12》

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To test if a coin is fair, the coin is flipped 100 times. It happens to land heads 62 times. This is more than the expected 50 h
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Answer:

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Step-by-step explanation:Answer:

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6 0
3 years ago
The range of which function is (2, infinity)? y = 2x y = 2(5x) y = 5x +2 y = 5x + 2
Sveta_85 [38]

Answer:

I think your functions are y=2^{x} ,y=2*5^{x} and y=2+5^{x}

If yes then then the third function which is y=2+5^{x}.

Step-by-step explanation:

The function c^{x} where c is a constant has

Domain : c\geq 0

Range : ( 0 , ∞ )

The above range is irrespective of the value of c.

I have attached the graph of each of the function, you can look at it for visualization.

  • <em>y=2^{x} ⇒ </em>This function is same as  c^{x} so its range is <em>( 0 , ∞ )</em>.
  • <em>y=2*5^{x} ⇒ </em>If we double each value of the function y=5^{x}, which has range ( 0 , ∞ ), but still the value of extremes won't change as 0*2=0 and ∞*2=∞. Therefore the range remains as <em>( 0 , ∞ )</em>.
  • <em>y=2+5^{x}</em> ⇒ If we add 2 to each value of the function y=5^{x}, which has range ( 0 , ∞ ), the lower limit will change as 0+2=2 but the upper limit will be same as ∞. Therefore the range will become as <em>( 2 , ∞ )</em>.

3 0
3 years ago
Read 2 more answers
Given the foci of (8,0) and the difference of the focal radii = 6, find the equation of the hyperbola
k0ka [10]

Given :

The foci of hyperbola are (8,0) and (-8,0) .

The difference of the focal radii = 6.

To Find :

The equation of the hyperbola.

Solution :

We know, distance between foci is given by :

2c = 8 - (-8)

c = 8

Also, difference between the foci or focal distance is given by :

2a = 6

a = 3

Now, we know for hyperbola :

b^2 +a^2 = c^2\\\\b^2={c^2-a^2}\\\\b^2 = 64-9\\\\b^2 = 55

General equation of hyperbola is :

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\\\\\dfrac{x^2}{9}+ \dfrac{y^2}{55}=1

Hence, this is the required solution.

3 0
3 years ago
So i picked b because it looked like the correct one? can someone tell me if it is
lukranit [14]
Yeah you are correct
6 0
3 years ago
Read 2 more answers
Help with thisssssss
Galina-37 [17]

Answer:

She made a mistake in step 3

She simplified the 3^-8 incorrectly

she should've added them

the answer is 3^24 if you need that

Step-by-step explanation:

using the following rule

b/x^{-n}=bx^n

we can see that she made a made a mistake in step 3 when simplifying

she should've added 3^8 to 3^16 rather than subtracting them

6 0
3 years ago
Read 2 more answers
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