Answer:
exywiyc yyey ey yyy yyy y y yy y yy yy y y y yyyy yyy y y y yy y y yy yy y y y y y yy y y y y y y y y y yAnswer:
exywiyc yyey ey yyy yyy y y yy y yy yy y y y yyyy yyy y y y yy y y yy yy y y y y y yy y y y y y y y y y y
Step-by-step explanation:Answer:
exywiyc yyey ey yyy yyy y y yy y yy yy y y y yyyy yyy y y y yy y y yy yy y y y y y yy y y y y y y y y y y
Answer:
I think your functions are
,
and 
If yes then then the third function which is
.
Step-by-step explanation:
The function
where c is a constant has
Domain : 
Range : ( 0 , ∞ )
The above range is irrespective of the value of c.
I have attached the graph of each of the function, you can look at it for visualization.
- <em>
⇒ </em>This function is same as
so its range is <em>( 0 , ∞ )</em>.
- <em>
⇒ </em>If we double each value of the function
, which has range ( 0 , ∞ ), but still the value of extremes won't change as 0*2=0 and ∞*2=∞. Therefore the range remains as <em>( 0 , ∞ )</em>.
- <em>
</em> ⇒ If we add 2 to each value of the function
, which has range ( 0 , ∞ ), the lower limit will change as 0+2=2 but the upper limit will be same as ∞. Therefore the range will become as <em>( 2 , ∞ )</em>.
Given :
The foci of hyperbola are (8,0) and (-8,0) .
The difference of the focal radii = 6.
To Find :
The equation of the hyperbola.
Solution :
We know, distance between foci is given by :
2c = 8 - (-8)
c = 8
Also, difference between the foci or focal distance is given by :
2a = 6
a = 3
Now, we know for hyperbola :

General equation of hyperbola is :

Hence, this is the required solution.
Answer:
She made a mistake in step 3
She simplified the 3^-8 incorrectly
she should've added them
the answer is 3^24 if you need that
Step-by-step explanation:
using the following rule

we can see that she made a made a mistake in step 3 when simplifying
she should've added 3^8 to 3^16 rather than subtracting them