No, John is incorrect.
<h3>
Correct work shown:</h3>
![\sf x^2 - 6x - 7 = 0](https://tex.z-dn.net/?f=%5Csf%20x%5E2%20-%206x%20-%207%20%3D%200)
![\sf x^2 - 6x = 7](https://tex.z-dn.net/?f=%5Csf%20x%5E2%20-%206x%20%3D%207)
![\sf x^2 - 6x + 9= 7 + 9](https://tex.z-dn.net/?f=%5Csf%20x%5E2%20-%206x%20%20%2B%209%3D%207%20%2B%209)
![\sf (x-3)^2= 16](https://tex.z-dn.net/?f=%5Csf%20%28x-3%29%5E2%3D%2016)
![\sf x-3=\pm \sqrt{16}](https://tex.z-dn.net/?f=%5Csf%20x-3%3D%5Cpm%20%5Csqrt%7B16%7D)
![\sf x-3= \pm 4](https://tex.z-dn.net/?f=%5Csf%20x-3%3D%20%5Cpm%204)
![\sf x= + 4 + 3 \quad or \quad x = -4 + 3](https://tex.z-dn.net/?f=%5Csf%20x%3D%20%2B%204%20%2B%203%20%5Cquad%20or%20%5Cquad%20x%20%3D%20-4%20%2B%203)
![\sf x= 7 \quad or \quad x = -1](https://tex.z-dn.net/?f=%5Csf%20x%3D%207%20%5Cquad%20or%20%5Cquad%20x%20%3D%20-1)
The correct answer should be x = 7 or x = -1
Answer:
Step-by-step explanation:
A rectangle has same opposite sides and 4 right angles as property of a rectangle.
The photo frame has different diagonal lengths
It makes opposite sides different, therefore it is not a rectangle
<u>Given angles (x - 20) and (x + 40) are consecutive interior angles which add up to 180°</u>
- x - 20° + x + 40° = 180°
- 2x + 20° = 180°
- 2x = 160°
- x = 80°
The answer is -40 but I don't remember how to calculate that, sorry.
Answer:
f⁻¹(x) = x+2 / 3
Step-by-step explanation:
Given function is:
f(x) = 3x-2
We have to find the inverse of the given function.
Put y = f(x) in given function, we have
y =3x-2
Adding 2 to both sides of the above equation we have
y+2 = 3x-2+2
y+2 = 3x
Dividing by 3 to both sides of the above equation, we have
y+2 / 3 = 3x / 3
y+2 / 3 = x
Put x = f⁻¹(y) in the above equation we have
y+2 / 3 = f⁻¹(y)
Swapping equation we have
f⁻¹(y) = y+2 / 3
Replace y with x we have
f⁻¹(x) = x+2 / 3 which is the answer.